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lesya692 [45]
3 years ago
11

An angle is created from points C, A, and B with vertex A. An arc is drawn from point A and intersects rays AC and AB. The inter

section of the arc and ray AC creates point D. The intersection of the arc and ray AB creates point E. An arc is drawn from point B. The compass is kept the same width and an additional arc is drawn from point E that intersects the arc drawn from point D. David is performing the following construction. Based on the markings that are present, what construction is he performing?
a.Bisecting an angle
b. Bisecting a line segment
c. Copying an angle
d. Copying a line segment
Mathematics
1 answer:
Minchanka [31]3 years ago
7 0

Answer:

Bisecting an angle ⇒ answer a

Step-by-step explanation:

* <em>Lets revise the steps of bisecting an angle</em>

- <em><u>How to construct a bisector of angle XYZ</u></em>

1. Open the compass to any width, and place its pin at the angle’s

   vertex Y and draw an arc cuts the two rays of the angle YX and YZ

   at two points M and N respectively

2. Open the compass to another width and place its pin at M and draw

    an arc between the two rays YX and YZ

3. Without changing the width of the compass place its pin at N and

   draw another arc intersects the arc from M at point Q

4. Join YQ which is the bisector of angle XYZ

* <em>Now lets compare these steps by the steps of the question</em>

∵ The vertex of the angle ABC is A represented by Y

∵ The rays of the angle AC and AB represented by YX and YZ

∵ Points D , E represented by points M , N

∴ The construction is " Bisecting an angle "

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If the null space of A4×5 is exactly a two-dimensional plane, answer the following:
Hatshy [7]

Answer:

I.

A is a 4 x 5 matrix => A: U -> V, dim U = 5, dim V = 4

Null space is exactly two dimensional plane

dim null (A) = 2

II.

Rank A = dim U - dim Null A = 5 - 2 = 3

III.

Number of linearly Independent columns of A is the rank of A = 3

IV.

Yes, The system Ax = b has no solution sometimes as range of A \neq V

V.

Yes,Sometimes Ax = b has a unique solution

VI.

Yes, sometimes Ax = b has infinitely many solutions

8 0
3 years ago
PLEASE HELP ME!!
Grace [21]
Take the derivative:
g’(x) = 12x^3 - 24x^2

Set equal to zero and solve:
0 = 12x^3 - 24x^2
0 = 12x^2 (x - 2)

x = 0 or x = 2

Plug back into original
g(0) = 3(0^4) - 8(0^3)
g(0) = 0 - 0
g(0) = 0

g(2) = 3(2^2) - 8(2^3)
g(2) = 3(4) - 8(8)
g(2) = 12 - 64
g(2) = -52

There is an absolute max at (0,0) or when x = 0
5 0
3 years ago
(31 x 15) + (108 divided by 6)=
Solnce55 [7]
465+18 = 483
The fraction was just to throw you off, it's not too hard if you look carefully since you get a whole number from it
4 0
3 years ago
Read 2 more answers
11 pounds 13 ounces = ounces
lawyer [7]
1 pound = 16 ounces so let's go ahead and convert 11 pounds to ounces by multiplying by 16. 11×16=176 and then add 13 to that 176+13=189

so 12 pounds and 13 ounces= 189 ounces


6 0
3 years ago
5. A yacht is cruising at 20 knots at bearing of 185° when a 15 knot wind starts to blow at a bearing of 290°. Find the directio
kicyunya [14]

Answer:

<em>Direction of the boat is 43.05° and the speed is 21.66 knot</em>

<em></em>

Step-by-step explanation:

yacht speed = 20 knots

yacht bearing = 185° = 85°  below the negative horizontal x-axis

wind speed = 15 knots

wind bearing = 290° = 20° above the negative horizontal x-axis

we find the x and y components of the boat velocities

for yacht,

x component = -20 cos 85° = -1.74 knots

y component = -20 sin 85° = -19.92 knots

for the wind,

x component = -15 cos 20° = -14.09 knots

y component = 15 sin 20° = 5.13 knots

total x component  Vx = -1.74 + (-14.09) = -15.83 knots

total y component Vy =  -19.92 + 5.13 = -14.79 knots

Resultant speed of the boat = \sqrt{Vx^{2} + Vy^{2}  }

==> \sqrt{15.83^{2} + 14.79^{2}  } = <em>21.66 knot</em>

<em></em>

direction of boat = tan^{-1} \frac{Vy}{Vx}

==> tan^{-1} \frac{14.79}{15.83} = <em>43.05°</em>

3 0
3 years ago
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