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pashok25 [27]
3 years ago
14

5p+9c=p solve for c I am confused on how to do it

Mathematics
1 answer:
Simora [160]3 years ago
8 0
Since <span><span>5p</span><span>5⁢p</span></span> does not contain the variable to solve for, move it to the right side of the equation by subtracting <span><span>5p</span><span>5⁢p</span></span> from both sides.<span><span><span>9c</span>=<span><span><span>−5</span>p</span>+p</span></span><span><span>9⁢c</span>=<span><span><span>-5</span>⁢p</span>+p</span></span></span>Add <span><span><span>−5</span>p</span><span><span>-5</span>⁢p</span></span> and <span>pp</span> to get <span><span><span>−4</span>p</span><span><span>-4</span>⁢p</span></span>.<span><span><span>9c</span>=<span><span>−4</span>p</span></span><span><span>9⁢c</span>=<span><span>-4</span>⁢p</span></span></span>Divide each term by <span>99</span> and simplify.
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there are 60 teams attend a chess tournament. every team will play with every other team exactly once. Supposed each team has a
Karolina [17]

The probability that no two teams win the same number of games, P ≈ 2.084 × 10⁻⁴⁵³

The reason for arriving at the above probability is as follows:

The given parameters are;

The number of teams in the tournament, n = 60

The chance of a team winning a game = 50% = 0.5

The number of ties = No ties

The required parameter:

The probability that no two teams win the same number of games

Method:

Calculate the number of ways no two teams win the same number of games, and divide the result by the total number of possible outcomes

Solution:

The number of matches played, n = \dbinom {60} {2} = 1,770

The possible outcomes = 2; Winning or losing

The total number of possible outcomes, n_p = 2¹⁷⁷⁰

The number of games won by each team is between 0 and 59

The ways in which no two teams won the same number of games is given by the games won by the teams to be 0, 1, 2,..., 57, 58, 59

Therefore, the number of ways no two teams won the same number of games, the required outcomes, n_k = 59!

Probability = \dfrac{Number \ of \ possible \ outcomes}{Number \ of \ required\ outcomes}

The probability that no two teams win the same number of games is given as follows;

\mathbf{P(No \ two \ teams \ won \ the \ same \ number \ of \ games)} = \dfrac{n_k}{n_p}

Therefore;

P(No \ two \ teams \ won \ the \ same \ number \ of \ games) = \dfrac{59!}{2^{1,770}} \approx \mathbf{2.084 \times 10^{-453}}

The probability that no two teams win the same number of games, P ≈ 2.084 × 10⁻⁴⁵³

Learn more about probability theory here:

brainly.com/question/1539712

3 0
3 years ago
If the relationship below are given in form (input, output), Which pairing always describes a function?
kozerog [31]

Answer:

Step-by-step explanation:

i'm not sure what the answer options are since they're not provided, but it's whichever option has a steady rate of change. (ex: money, time spent earning it; location, time spent driving; length in inches, length in meters)

3 0
3 years ago
Can anyone pls help me with this question ?
bagirrra123 [75]

Answer:

B

Step-by-step explanation:

When the function is less than but equal to and it's opposite are always solid dots. By this you can do simple process of elimination.

6 0
3 years ago
The sides of a quadrilateral are x,x+3,x+4,x+5. it’s perimeter is 52, find the lengths of the sides
wariber [46]

Answer: 10 , 13 , 14 , 15

Step-by-step explanation:

To find the perimeter of a quadrilateral , we will add all its side , that is

Perimeter = x + x + 3 + x + 4 + x + 5

That is

52 = x + x + 3 + x + 4 + x + 5

52 = 4x + 12

subtract 12 from both sides

40 = 4x

divide through by 4

x = 10

therefore , the lengths of the sides are

10 , 10+3 , 10 + 4 , 10 + 5 , that is

10 , 13 , 14 , 15

4 0
4 years ago
Which ones correct?
natima [27]

Answer:

D

Step-by-step explanation:

y = 4 is a horizontal line which would be parallel to the x axis

6 0
3 years ago
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