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3 years ago

Two spherical balloons are filled with water. The first balloon has a radius of 3 cm, and the second has a radius of 6 cm.

Mathematics

2 answers:

ArbitrLikvidat [17]3 years ago

7 0

Answer:

Answer is 791.28 $cm^{3}$

Step-by-step explanation:

First we need to calculate the volume of each balloons by using the formula

volume of sphere with radius r is

V = 4/3 π $r^{3}$

Balloon 1.

r1 = 3 cm

V1 = 4/3 × 3.14 × $3^{3}$

V1 = 113.04 $cm^{3}$

Balloon 2.

r2 = 6 cm

V2 = 4/3 × 3.14 × $6^{3}$

V2 = 904.32 $cm^{3}$

Therefore we subtract small volume of balloon from large volume of balloon

= V2 - V1

= 904.32 $cm^{3}$ - 113.04 $cm^{3}$

= 904.32 - 113.04 = 791.28 $cm^{3}$

Minchanka [31]3 years ago

5 0

<span>all you do to calculate the volume is 4/3*3.14*r^3</span>

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