Answer:
For this case we want to test if the the average monthly income of all students at college is at least $2000. Since the alternative hypothesis can't have an equal sign thne the correct system of hypothesis for this case are:
Null hypothesis (H0): ![\mu \geq 2000](https://tex.z-dn.net/?f=%5Cmu%20%5Cgeq%202000)
Alternative hypothesis (H1): ![\mu](https://tex.z-dn.net/?f=%5Cmu%20%3C2000)
And in order to test this hypothesis we can use a one sample t or z test in order to verify if the true mean is at least 200 or no
Step-by-step explanation:
For this case we want to test if the the average monthly income of all students at college is at least $2000. Since the alternative hypothesis can't have an equal sign thne the correct system of hypothesis for this case are:
Null hypothesis (H0): ![\mu \geq 2000](https://tex.z-dn.net/?f=%5Cmu%20%5Cgeq%202000)
Alternative hypothesis (H1): ![\mu](https://tex.z-dn.net/?f=%5Cmu%20%3C2000)
And in order to test this hypothesis we can use a one sample t or z test in order to verify if the true mean is at least 2000 or no
Answer:
i dont know i dont understand the question
I tried my best to explain it...dm me if you still don’t understand
Hope this helped :)
Answer:
<h3> YES</h3>
Step-by-step explanation:
relation is a function if we have y for every x from domain and for one x we have one and only one y
x = 1 --> y = 2
x = 2 --> y = 2
x = -2 --> y = 2
no x-es without y-es
and no two the same x-es with one y
so this relation is a function