Answer:
d) 135º
Step-by-step explanation:
Note that the angle DCU is the sum of the angles DCB and BCU. The angle DCB is 90º because A B C D is a square, then all its angles are equal to 90º.
After attaching B U C to A B C D, we obtain a trapezoid A U C D. Since A U C D has at least one pair of parallel sides, then AU should be parallel to CD, thus the angle CBU must be 90º.
B U C is isoceles, so we conclude that other two angles must have the same size, and due to the sum of the angles of a triangle being 180º, then both BUC and BCU are equal to 45º
As a result, the angle DCU is equal to 90º+45º = 135º. Option d is the correct one.
0.9874 the greatest non zero place is 9 but the nearest digit is 8 when you round it off to 0.9 the answer becomes 1.0
0.9874~1.0
Y=3/4x+2 cus u subtract than divide
Any line can be expressed in the form y=mx+b where m is the slope and b is y intercept.
Two lines can either be parallel ,overlap or meet at one point .Let us look at different cases :
1)When two lines are parallel they do not intersect at any point and hence the system of equations have no solution.
2) When two lines overlap each other then the two lines touch each other at infinite number of points and we say the system of equations have infinite solutions.
3) When two lines intersect each other at one point we say the system of equation has one solution.
Part A:
The given lines are intersecting at one point so we have one solution.
Part B:
The point of intersection is the solution to the system of equations .In the graph the point of intersection of the lines is (4,4)
Solution is (4,4)
Answer:
<em>U'</em>(3, -6), <em>V</em><em>'</em>(8, -1), <em>W</em><em>'</em>(3, -1)
Step-by-step explanation:
According to the <em>180°-rotation rule</em>, you take the OPPOSITE of both the y-coordinate and x-coordinate:
<u>Extended Rotation Rules</u>
270°-clockwise rotation [90°-counterclockwise rotation] >> (x, y) → (-y, x)
270°-counterclockwise rotation [90°-clockwise rotation] >> (x, y) → (y, -x)
180°-rotation >> (x, y) → (-x, -y)
I am joyous to assist you anytime.
