Answer:
Step-by-step explanation:
Answer:
15.6 ft²
Step-by-step explanation:
Given:
Radius (r) of circle = 5.7 ft
m<CBD = 55°
Required: Area of the shaded sector
SOLUTION:
Area of shaded sector = θ/360*πr²
Where,
θ = 55°
π = 3.14
r = 5.7 ft
Plug in your values
![Area = \frac{55}{360}*3.14*5.7^2](https://tex.z-dn.net/?f=%20Area%20%3D%20%5Cfrac%7B55%7D%7B360%7D%2A3.14%2A5.7%5E2%20)
![Area = \frac{55}{360}*3.14*32.49](https://tex.z-dn.net/?f=%20Area%20%3D%20%5Cfrac%7B55%7D%7B360%7D%2A3.14%2A32.49%20)
![Area = 15.59](https://tex.z-dn.net/?f=%20Area%20%3D%2015.59%20)
Area of shaded sector to nearest tenth = 15.6 ft²
Answer:
you told me to resolve this problem
Step-by-step explanation:
Answer:
<h2>(-1, 17)</h2>
Step-by-step explanation:
The vertex form of a quadratic equation:
![y=a(x-h)^2+k](https://tex.z-dn.net/?f=y%3Da%28x-h%29%5E2%2Bk)
<em>(h, k)</em> - vertex
![y=x^2+2x+18](https://tex.z-dn.net/?f=y%3Dx%5E2%2B2x%2B18)
<em>use (a + b)² = a² + 2ab + b² </em><em>(*)</em>
![y=\underbrace{x^2+2(x)(1)+1^2}_{(*)}-1+18](https://tex.z-dn.net/?f=y%3D%5Cunderbrace%7Bx%5E2%2B2%28x%29%281%29%2B1%5E2%7D_%7B%28%2A%29%7D-1%2B18)
![y=(x+1)^2+17\\\\y=(x-(-1))^2+17](https://tex.z-dn.net/?f=y%3D%28x%2B1%29%5E2%2B17%5C%5C%5C%5Cy%3D%28x-%28-1%29%29%5E2%2B17)
<em>h = -1, k = 17</em>