S, P.
S is a sphere
P is an infinity
Answer:
49.14 carat.
Explanation:
From the question given above, we obtained the following data:
Volume of diamond = 2.8 mL
Mass of diamond (in carat) =.?
Next, we shall determine the mass of diamond in grams (g). This can be obtained as follow:
Volume of diamond = 2.8 mL
Density of diamond = 3.51 g/mL
Mass of diamond ( in grams) =?
Density = mass /volume
3.51 = mass /2.8
Cross multiply
Mass of diamond (in g) = 3.51 × 2.8
Mass of diamond (in g) = 9.828 g
Finally, we shall Convert 9.828 g to carat. This can be obtained as follow:
1 g = 5 carat
Therefore,
9.828 g = 9.828 g /1 g × 5 carat
9.828 g = 49.14 carat.
Therefore, the mass of the diamond in carat is 49.14 carat.
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I don't understand your question
Here we have to get the effect of addition of 0.25 moles of gas C on the mole fraction of gas A in a mixture of gas having constant pressure.
On addition of 0.25 moles of C gas, the mole fraction of gas A will be 
.
The partial pressure of gas A can be written as 
= 
×P (where is the mole fraction of gas A present in the mixture and P is the total pressure of the mixture.
The mole fraction of gas A in a mixture of gas A and C is = 
and 
respectively.
Thus on addition of 0.25 moles of C gas, the mole fraction of gas A will be .
Which is different from the initial state.
