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poizon [28]
4 years ago
15

Sludge and water mixture is homogeneous or heterogeneous mixture?

Chemistry
1 answer:
dlinn [17]4 years ago
3 0

Answer:

It is a heterogeneous mixture

Explanation:

A mixture is a substance that is formed by several components (two or more), which do not lose their properties and characteristics due to the mixing because there is no chemical reaction between them.

<u> Homogeneous mixtures</u>: Those mixtures whose components cannot be distinguished with the naked eye. The homogeneous mixtures of liquids are known as solutions and consist of a solute and a solvent, the first being the one in smaller proportion and also usually the liquid. For example, water mixed with mineral salts or sugar, water would be the solvent and sugar the solute.

<u>Heterogeneous Mixtures</u>: A heterogeneous mixture is one that has a non-uniform composition in which its components can be distinguished with the naked eye and is formed by two or more substances, physically different, unevenly distributed. The parts of a heterogeneous mixture can be separated mechanically. For example, water and sand, <u>water and sludge</u>, water and oil

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1. According to the equation, what mass of hydrogen fluoride is necessary to produce 2.3 g of sodium fluoride?
Luba_88 [7]

Answer:

1.09 grams

Explanation:

According to the following chemical equation:

HF + NaNO₃ -> HNO₃ + NaF

1 mol of hydrogen fluoride (HF) produces 1 mol of sodium fluoride (NaF). Thus, we first convert from mol to grams by using the molar mass (MM) of each compound:

MM(HF)= (1 g/mol x 1 H) + (19 g/mol x 1 F) = 20 g/mol HF

1 mol HF x 19.9 g/mol HF = 20 g

MM(NaF) = (23 g/mol x 1 Na) + (19 g/mol x 1 F) = 42 g/mol NaF

1 mol NaF x 42 g/mol NaF = 42 g

Thus, from 20 g of HF are produced 42 g of NaF  ⇒ 20 g HF/42 g NaF. We multiply this stoichiometric ratio by the mass of NaF produced to calculate the required mass of HF:

20 g HF/42 g NaF x 2.3 g NaF = 1.09 g HF

Therefore, 1.09 grams of HF are necessary to produce 2.3 g of NaF.

5 0
3 years ago
Why does the s orbital fill before the p orbitals?
worty [1.4K]
The answer is B. The s orbital holds a maximum of 2 electrons, where the p orbital holds a maximum of 6 electrons.
3 0
3 years ago
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HELPPP ME WITH SICENCE PLZZZZZZ
Goryan [66]

Answer:

molecules

Explanation:

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Which of the following is a lanthanide
Gelneren [198K]

Answer:

Hope it helps.

Explanation:

The lanthanide (/ˈlænθənaɪd/) or lanthanoid (/ˈlænθənɔɪd/) series of chemical elements[1] comprises the 15 metallic chemical elements with atomic numbers 57–71, from lanthanum through lutetium.[2][3][4] These elements, along with the chemically similar elements scandium and yttrium, are often collectively known as the rare earth elements.

The informal chemical symbol Ln is used in general discussions of lanthanide chemistry to refer to any lanthanide. All but one of the lanthanides are f-block elements, corresponding to the filling of the 4f electron shell; depending on the source, either lanthanum or lutetium is considered a d-block element, but is included due to its chemical similarities with the other 14.[5] All lanthanide elements form trivalent cations, Ln3+, whose chemistry is largely determined by the ionic radius, which decreases steadily from lanthanum to lutetium.

They are called lanthanides because the elements in the series are chemically similar to lanthanum. Both lanthanum and lutetium have been labeled as group 3 elements, because they have a single valence electron in the 5d shell. However, both elements are often included in discussions of the chemistry of lanthanide elements. Lanthanum is the more often omitted of the two, because its placement as a group 3 element is somewhat more common in texts and for semantic reasons: since "lanthanide" means "like lanthanum", it has been argued that lanthanum cannot logically be a lanthanide, but IUPAC acknowledges its inclusion based on common usage.[6]

In presentations of the periodic table, the lanthanides and the actinides are customarily shown as two additional rows below the main body of the table,[2] with placeholders or else a selected single element of each series (either lanthanum and actinium, or lutetium and lawrencium) shown in a single cell of the main table, between barium and hafnium, and radium and rutherfordium, respectively. This convention is entirely a matter of aesthetics and formatting practicality; a rarely used wide-formatted periodic table inserts the lanthanide and actinide series in their proper places, as parts of the table's sixth and seventh rows (periods).

The 1985 International Union of Pure and Applied Chemistry “Red Book” (p. 45) recommends that "lanthanoid" is used rather than "lanthanide". The ending “-ide” normally indicates a negative ion. However, owing to wide current use, “lanthanide” is still allowed.

6 0
3 years ago
Read 2 more answers
When fluoride reacts with the metal it forms an F negative ion the fluorine Adam has gained an electron an undergone _______.
Anika [276]

Answer:

Reduction.

Explanation:

Fluorine atom has gained an electron and undergone reduction because when an atom gains electron it reduced itself thus acting as an oxidant to oxidize another atom .

   For exam sodium fluoride  NaF is a salt when sodium fluoride undergo breakdown at that time the fluoride atom gains an electron and is converted to F- anion by the process called reduction .

4 0
3 years ago
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