Answer:
1.53 × 10²³ molecules As₂O₃
Explanation:
Step 1: Define
Diarsenic Trioxide - As₂O₃
Avagadro's number: 6.02 × 10²³ atoms, molecules, formula units, etc.
Step 2: Use Dimensional Analysis
= 1.52908 × 10²³ molecules As₂O₃
Step 3: Simplify
We have 3 sig figs.
1.52908 × 10²³ molecules As₂O₃ ≈ 1.53 × 10²³ molecules As₂O₃
<span>The answer should be Uranium. As tiny amounts of that (rods normally) can fuel a whole nuclear energy station for years.</span>
Answer:
19 g
Explanation:
Data Given:
Sodium Chloride (table salt) = 50 g
Amount of sodium (Na) = ?
Solution:
Molecular weight calculation:
NaCl = 23 + 35.5
NaCl = 58.5 g/mol
Mass contributed by Sodium = 23 g
calculate the mole percent composition of sodium (Na) in sodium Chloride.
Since the percentage of compound is 100
So,
Percent composition of sodium (Na) = 23 / 58.5 x 100
Percent of sodium (Na) = 39.3 %
It means that for ever gram of sodium chloride there is 0.393 g of Na is present.
So,
for the 50 grams of table salt (NaCl) the mass of Na will be
mass of sodium (Na) = 0.393 x 50 g
mass of sodium (Na) = 19 g
Answer:
a = 4
b = 3
Explanation:
<u>SOLUTION :-</u>
Balance it by using 'hit & trial' method , and you'll get the answer :-
2Fe₂O + 3C → <u>4</u>Fe + <u>3</u>CO₂
⇒ a = 4 ; b = 3
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<u>VERIFICATION :-</u>
<em>In reactant side of equation :-</em>
- Number of atoms in Fe = 2×2 = 4
- Number of atoms in O = 2×3 = 6
- Number of atoms in C = 3×1 = 3
<em>In product side of equation :-</em>
- Number of atoms in Fe = 4×1 = 4
- Number of atoms in C = 3×1 = 3
- Number of atoms in O = 3×2 = 6
Number of atoms of each element is equal in both reactant & product side of equation. Hence , the equation is balanced.
