Answer:
Probability that the respondent has a pet given that the respondent has had a pet is
or 0.46.
Step-by-step explanation:
We are given the following results below;
37% have a pet now and have had a pet.
63% do not have a pet now.
81% have had a pet.
19% do not have a pet now and have never had a pet.
Let event B = respondent has a pet now
Now, Probability that the respondent has had a pet = P(A) = 0.81
Probability that the respondent has a pet now and has had a pet =
= 0.37
So, Probability that the respondent has a pet given that the respondent has had a pet is given by = P(B/A)
<u>This conditional probability is solved as ;</u>
P(B/A) =
=
= 0.46.
Answer:
40 cubes
Step-by-step explanation:
multiply side lengths or the prism by 2, then solve for volume
2.5 * 2 = 5
2 * 2 = 4
1 * 2 = 2
5 * 4 * 2 = 40
So, 9 out of 10 students prefer class, so, obviously, it would not be 100. It would be 150. So in conclusion, 50 students prefer lunch over math class, whilst 150 other students prefer math class over lunch.
Answer:
C
Step-by-step explanation:
Answer:
V > -15
Step-by-step explanation:
