The graph of this equation is an exponential equation. On the left side of the y-axis it is very small. Then on the right side, it goes up quickly.
The following are all true:
The domain is all numbers.
The y-intercept is (0, 2)
It is increasing.
Answer:
Step-by-step explanation:
We want to solve the equation:
In the interval [0, 2π).
Notice that this is in quadratic form. Namely, by letting u = sin(θ), we acquire:
Factor:
By the Zero Product Property:
Solve for each case:
Back-substitute:
Use the Unit Circle. Hence, our three solutions in the interval [0, 2π) are:
<h3>
Answer:</h3>
The real solutions are -5, -4, 4, 5. There are no complex solutions.
<h3>
Step-by-step explanation:</h3>
The equation ...
... x^4 -41x^2 +400 = 0
can be factored as ...
... (x^2 -16)(x^2 -25) = 0
... (x -4)(x +4)(x -5)(x +5) = 0
So, all roots are real and are ...
... x ∈ {-5, -4, 4, 5}
_____
These are the values of x that make the factors zero.
Answer:
It is not true. 19 - 10 = 9.
:) Hope this helps
Answer:
x^3+2x^2-x-2=(x+2)(x-1)(x+1)
The other two factors are x-1 and x+1
Step-by-step explanation:
Use synthetic division:
x^3+2x^2-x-2 / x+2
-2 | 1 2 -1 -2
-2 0 2
_________
1 0 -1 0
This means x^2-1 with no remainder, but we can still break it down. The factors of -1 are 1 and -1, so we must find the factors:
1 | 1 0 -1
1 1
______
1 1 0
This means x+1 so that's one factor
-1 | 1 0 -1
-1 1
_______
1 -1 0
This means x-1 so that's the other factor
Thus, the factors of x^3+2x^2-x-2 are (x+2)(x+1)(x-1)