How many 3 go in 76 for math

A rectangular computer monitor is measured by the length and width of its display resolution. Three different monitors are descr

Anna [14]

Answer: Monitors A and B

Step-by-step explanation:

The similar monitors based on display resolution are those with similar ratios.

Take the ratios to their simplest forms to see which are similar.

Monitor A

= 640 : 480

= 16 : 12

= 4 : 3

Monitor B

= 800 : 600

= 8 : 6

= 4 : 3

Monitor C

= 1,280 : 800

= 32 : 20

= 8 : 5

Monitors A and B are similar as they have the same display ratio.

3 0

3 years ago

Question 6 options: What is the approximate area of a circle with a diameter of 56 cm? Use your calculator button for π. Round y

Andrew [12]

The area of circle is 2463.0086 cm².

Step-by-step explanation:

Given,

Diameter of circle = 56 cm

Radius of circle = $\frac{Diameter}{2}$

Radius of circle = $\frac{56}{2}=28\ cm$

We know that;

Area of circle = $\pi r^2$

Area of circle = $\pi *(28)^2$

Area of circle = π * 784

Area of circle = 2463.00864041 cm²

Rounding off to four decimal places

Area of circle = 2463.0086 cm²

The area of circle is 2463.0086 cm².

Keywords: area, circle

Learn more about area at:

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8 0

3 years ago

Find the average value of the function f(t)=(t-2)^2 on [0,6]

pentagon [3]

Answer:

2

Step-by-step explanation:

The "average value of function f(x) on interval [a, b] is given by:

f(b) - f(a)

ave. value = ---------------

b - a

Here f(t)=(t-2)^2.

Thus, f(b) = (b - 2)^2. For b = 6, we get:

f(6) = 6^2 - 4(6) + 4, or f(6) = 36 - 24 + 4 = 16

For a = 0, we get:

f(0) = (0 - 2)^2 = 4

Plugging these results into the ave. value function shown above, we get:

16 - 4

ave. value = ------------ = 12/6 = 2

6 - 0

The average value of the function f(t)=(t-2)^2 on [0,6] is 2.

4 0

3 years ago

Use complete sentences to describe why √-1 ≠ -√1

tekilochka [14]

Well let's say that to compare these two numbers, we have to start with the definition first.

Definition

$\displaystyle \large{ {y}^{2} = x} \\ \displaystyle \large{ y = \pm \sqrt{x} }$

Looks like we can use any x-values right? Nope.

The value of x only applies to any positive real numbers for one reason.

As we know, any numbers time itself will result in positive. No matter the negative or positive.

Definition II

$\displaystyle \large{ {a}^{2} = a \times a = |b| }$

Where b is the result from a×a. Let's see an example.

Examples

$\displaystyle \large{ {2}^{2} = 2 \times 2 = 4} \\ \displaystyle \large{ {( - 2)}^{2} = ( - 2) \times ( - 2) = | - 4| = 4}$

So basically, their counterpart or opposite still gives same value.

Then you may have a question, where does √-1 come from?

It comes from this equation:

$\displaystyle \large{ {y}^{2} = - 1}$

When we solve the quadratic equation in this like form, we square both sides to get rid of the square.

$\displaystyle \large{ \sqrt{ {y}^{2} } = \sqrt{ - 1} }$

Then where does plus-minus come from? It comes from one of Absolute Value propety.

Absolute Value Property I

$\displaystyle \large{ \sqrt{ {x}^{2} } = |x| }$

Solving absolute value always gives the plus-minus. Therefore...

$\displaystyle \large{ y = \pm \sqrt{ - 1} }$

Then we have the square root of -1 in negative and positive. But something is not right.

As I said, any numbers time itself of numbers squared will only result in positive. So how does the equation of y^2 = -1 make sense? Simple, it doesn't.

Because why would any numbers squared result in negative? Therefore, √-1 does not exist in a real number system.

Then we have another number which is -√1. This one is simple.

It is one of the solution from the equation y^2 = 1.

$\displaystyle \large{ {y}^{2} = 1} \\ \displaystyle \large{ \sqrt{ {y}^{2} } = \sqrt{1} } \\ \displaystyle \large{ y = \pm \sqrt{1} }$

We ignore the +√1 but focus on -√1 instead. Of course, we know that numbers squared itself will result in positive. Since 1 is positive then we can say that these solutions exist in real number.

Conclusion

So what is the different? The different between two numbers is that √-1 does not exist in a real number system since any squared numbers only result in positive while -√1 is one of the solution from y^2 = 1 and exists in a real number system.

5 0

2 years ago

Read 2 more answers

A rectangular swimming pool measures 7.5 m by 4.5 m. It is completely surrounded by a fence parallel to each edge of the pool an

Illusion [34]

The total length of the fence is 48 m if the rectangular swimming pool measures 7.5 m by 4.5 m.

<h3>What is rectangle?</h3>

It is defined as the two-dimensional geometry in which the angle between the adjacent sides are 90 degree. It is a type of quadrilateral.

It is defined as the area occupied by the rectangle in two-dimensional planner geometry.

The area of a rectangle can be calculated using the following formula:

Rectangle area = length x width

It is given that:

A rectangular swimming pool measures 7.5 m by 4.5 m.

It is completely surrounded by a fence parallel to each edge of the pool and at a distance of 3 m from each edge of the pool.

The total length of the fence = 2(7.5+3×2 + 4.5+3×2)

The total length of the fence = 2(7.5+6 + 4.5+6)

The total length of the fence = 2(24)

The total length of the fence = 48 m

Thus, the total length of the fence is 48 m if the rectangular swimming pool measures 7.5 m by 4.5 m.

Learn more about the rectangle here:

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4 0

2 years ago