The objective function is simply a function that is meant to be maximized. Because this function is multivariable, we know that with the applied constraints, the value that maximizes this function must be on the boundary of the domain described by these constraints. If you view the attached image, the grey section highlighted section is the area on the domain of the function which meets all defined constraints. (It is all of the inequalities plotted over one another). Your job would thus be to determine which value on the boundary maximizes the value of the objective function. In this case, since any contribution from y reduces the value of the objective function, you will want to make this value as low as possible, and make x as high as possible. Within the boundaries of the constraints, this thus maximizes the function at x = 5, y = 0.
10-4=6. can it be like this.
Answer:
r = 5y/8
Step-by-step explanation:
isolate the variable by dividing each side by factors that contain the variable.
For a cube,
The volume is the cube of the side length.
To raise a product to an exponent, raise each factor to the exponent.
To raise a power to a power, multiply powers.
As a percent is out of 100% or 1 (as a whole number), the best thing to do is multiply it by ten, until you get a whole number. As you cannot have a decimal in a percentage. 2.45x10= 24.5. This is still a decimal, so you need to multiply it be ten again, 24.5x10= 245.
Therefore, 2.45 is a percent is 245%