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2 years ago

12

What type of triangle, if any, can be formed with sides measuring 8 inches, 8 inches, and 3 inches?

1 answer:

MissTica2 years ago

5 0

We can form an Isosceles triangle using the given measures. Step-by-step explanation: We are given the measure of three sides of a triangle.

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Which of the following represents a function?

Molodets [167]

What are the functions?

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2 years ago

Solve the initial value problem y'=2 cos 2x/(3+2y),y(0)=−1 and determine where the solution attains its maximum value.

zloy xaker [14]

Answer:

$y=\frac{-3\pm\sqrt{4sin2x+1}}{2}$

$x={\pi}{4}$

Step-by-step explanation:

We are given that

$y'=\frac{2cos2x}{3+2y}$

y(0)=-1

$\frac{dy}{dx}=\frac{2cos2x}{3+2y}$

$(3+2y)dy=2cos2x dx$

Taking integration on both sides then we get

$\int (3+2y)dy=2\int cos 2xdx$

$3y+y^2=sin2x+C$

Using formula

$\int x^n=\frac{x^{n+1}}{n+1}+C$

$\int cosx dx=sinx$

Substitute x=0 and y=-1

$-3+1=sin0+C$

$-2=C$

$sin0=0$

Substitute the value of C

$y^2+3y=sin2x-2$

$y^2+3y-sin 2x+2=0$

$y=\frac{-3\pm\sqrt{(3)^2-4(1)(-sin2x+2)}}{2}$

By using quadratic formula

$x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$

$y=\frac{-3\pm\sqrt{9+4sin2x-8}}{2}=\frac{-3\pm\sqrt{4sin2x+1}}{2}$

Hence, the solution $y=\frac{-3\pm\sqrt{4sin2x+1}}{2}$

When the solution is maximum then y'=0

$\frac{2cos2x}{3+2y}=0$

$2cos2x=0$

$cos2x=0$

$cos2x=cos\frac{\pi}{2}$

$cos\frac{\pi}{2}=0$

$2x=\frac{\pi}{2}$

$x=\frac{\pi}{4}$

3 0

2 years ago

2.35 ÷ (-1.5) (Round to the tenth)

Sidana [21]

-1.6 is your answer :))))

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2 years ago

Hey please sorry its three questions thank you.

Karo-lina-s [1.5K]

Bacd the ancestors

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2 years ago

You and a friend sign up for a health club. It costs $50 to join, plus $20 a month. However, the first 100 customers can sign up

faltersainse [42]

You- y=50+20x
friend y=30+20x
If you subtract, the difference is only 20 dollars at any given months since the rates are the same

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2 years ago