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Rashid [163]
3 years ago
8

In circle O below, what is the measure of arc ED?

Mathematics
1 answer:
Serga [27]3 years ago
5 0
Triangle FOD is an isosceles with base FD.
FD = 2 · 4 = 8
FD = CB
Arc CB = 56°
Arc ED = 1/2 Arc FD = 1/2 Arc CB
Arc ED = 56° : 2
Answer:
Arc ED = 28° 

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The function g is defined as follows for the domain given. g(x) = 2 - 2x , domain = \{- 1, 0, 1, 2\} Write the range of g using
Musya8 [376]

Explanation:

The function is given below as

g(x)=2-2x

The set of domains is given below as

\lbrace-1,0,1,2\rbrace

Step 1:

Put x=-1

\begin{gathered} g(x)=2-2x \\ g(-1)=2-2(-1) \\ g(-1)=2+2 \\ g(-1)=4 \end{gathered}

Step 2:

Put x=0

\begin{gathered} g(x)=2-2x \\ g(0)=2-2(0) \\ g(0)=2 \end{gathered}

Step 3:

Put x=1

\begin{gathered} g(x)=2-2x \\ g(1)=2-2(1) \\ g(1)=2-2 \\ g(1)=0 \end{gathered}

Step 4:

Put x=2

\begin{gathered} g(x)=2-2x \\ g(2)=2-2(2) \\ g(2)=2-4 \\ g(2)=-2 \end{gathered}

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The range of g(x) using set notation will be

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1 year ago
Jensen Tire & Auto is in the process of deciding whether to purchase a maintenance contract for its new computer wheel align
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Answer:

Step-by-step explanation:

Hello!

The given data corresponds to the variables

Y:  Annual Maintenance  Expense ($100s)

X: Weekly Usage  (hours)

n= 10

∑X= 253; ∑X²= 7347; \frac{}{X}= ∑X/n= 253/10= 25.3 Hours

∑Y= 346.50; ∑Y²= 13010.75; \frac{}{Y}= ∑Y/n= 346.50/10= 34.65 $100s

∑XY= 9668.5

a)

To estimate the slope and y-intercept you have to apply the following formulas:

b= \frac{sumXY-\frac{(sumX)(sumY)}{n} }{sumX^2-\frac{(sumX)^2}{n} } = \frac{9668.5-\frac{253*346.5}{10} }{7347-\frac{(253)^2}{10} }= 0.95

a= \frac{}{Y} -b\frac{}{X} = 34.65-0.95*25.3= 10.53

^Y= a + bX

^Y= 10.53 + 0.95X

b)

H₀: β = 0

H₁: β ≠ 0

α:0.05

F= \frac{MS_{Reg}}{MS_{Error}} ~~F_{Df_{Reg}; Df_{Error}}

F= 47.62

p-value: 0.0001

To decide using the p-value you have to compare it against the level of significance:

If p-value ≤ α, reject the null hypothesis.

If p-value > α, do not reject the null hypothesis.

The decision is to reject the null hypothesis.

At a 5% significance level you can conclude that the average annual maintenance expense of the computer wheel alignment and balancing machine is modified when the weekly usage increases one hour.

b= 0.95 $100s/hours is the variation of the estimated average annual maintenance expense of the computer wheel alignment and balancing machine is modified when the weekly usage increases one hour.

a= 10.53 $ 100s is the value of the average annual maintenance expense of the computer wheel alignment and balancing machine when the weekly usage is zero.

c)

The value that determines the % of the variability of the dependent variable that is explained by the response variable is the coefficient of determination. You can calculate it manually using the formula:

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This means that 86% of the variability of the annual maintenance expense of the computer wheel alignment and balancing machine is explained by the weekly usage under the estimated model ^Y= 10.53 + 0.95X

d)

Without usage, you'd expect the annual maintenance expense to be $1053

If used 100 hours weekly the expected maintenance expense will be 10.53+0.95*100= 105.53 $100s⇒ $10553

If used 1000 hours weekly the expected maintenance expense will be $96053

It is recommendable to purchase the contract only if the weekly usage of the computer is greater than 100 hours weekly.

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Answer:

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