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riadik2000 [5.3K]
4 years ago
7

What did the friend do wrong in this equation?

Mathematics
1 answer:
rjkz [21]4 years ago
4 0

Answer:

4x + 2x = 90 NOT 180.

Step-by-step explanation:

x = 15 is the correct answer.

You might be interested in
A property contained ten acres. How many lots of not less than 50 feet by 100 feet can be subdivided from the property if 26,000
NemiM [27]

Answer:

81 lots of 5,000 square feet fits in the property.

Step-by-step explanation:

<em><u>The first step </u></em>is calculate the square feet of the minimum area:

50 \: feets \times 100 \: feet = 5,000 \:square \: feet

<em><u>Second,</u></em> from the ten acres we subtract the 26,000 feets of roads:

1 \: acre = 60 \: feet \times 660\:feet = 43,560\:square\:feet\\43,560 \times 10 = 435,600\\435,600 - 26,000 = 409,600 \:square \: feet\:available

<em><u>Third,</u></em> we divide the lot area over the available square feet

\frac{409,600}{5,000} = 81.92

81 lots of 5,000 square feet fits in the property.

7 0
4 years ago
The label on a can of lemonade gives the volume as 12 fl oz or 355ml . Verify that these two measurements are nearly equivalent
liraira [26]

We have been given that the label on a can of lemonade gives the volume as 12 fl oz or 355 ml and we are asked to verify that these two measurements are nearly equivalent.

Since we know that 1 fluid ounce equals 29.5735 ml. Let us find volume of lemonade can in ml by multiplying 12 by 29.5735.

\text{Volume of can}=12\cdot29.5735

\text{Volume of can}=354.882

\text{Volume of can}=354.882\approx355

We can see that 354.882 is nearly equivalent to 355. Therefore, we can say that these two measurements are nearly equivalent.


6 0
4 years ago
Increase by 40% (write the decimal multuplier)​
DanielleElmas [232]

Answer: 0.040

Step-by-step explanation:

6 0
3 years ago
I need help and plez
Ksivusya [100]
100 / 120 / 121
10 11
Hope this helps
3 0
3 years ago
Find any relative extrema of the function. (Round your answers to three decimal places.)
Strike441 [17]

(x) = arcsec(x) − 8x

f'(x) = d/dx( arcsec(x) − 8x )

<span> 1/xsqrt( x^2 - 1) - 8</span>

f'(x) = 0

1/xsqrt( x^2 - 1) - 8 = 0

8 x sqrt (x^2-1) = 1

<span> ( 8 x sqrt (x^2-1) )^2 = 1</span>

64 x^2 ( x^2 - 1) = 1

64 x^4 - 64 x^2 =1

64 x^4 - 64 x^2 - 1 = 0

x = 1.00766 , - 1.00766

<span> x =   - 1.00766</span>

f(- 1.00766) = arcsec(- 1.00766) − 8( - 1.00766)

f( - 1.00766 ) = 11.07949

x = 1.00766

f(1.00766) = arcsec(1.00766) − 8( 1.00766)

f(1.00766 ) = -7.93790

relative maximum (x, y) = (- 1.00766 , 11.07949 ) relative minimum (x, y) = ( 1.00766 , -7.93790  )


8 0
4 years ago
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