The question here is how long does it take for a falling
person to reach the 90% of this terminal velocity. The computation is:
The terminal velocity vt fulfills v'=0. Therefore vt=g/c,
and so c=g/vt = 10/(100*1000/3600) = 36,000/100,000... /s. Incorporating the
differential equation shows that the time needed to reach velocity v is
t= ln [g / (g-c*v)] / c.
With v=.9 vt =.9 g/c,
t = ln [10] /c = 6.4 sec.
Answer:if it’s a pretest just guess you don’t need to get it right
Step-by-step explanation:
Hot Dog Stand
Let
C--------> total cost of the hot dog
x-------> is the number of toppings
we know that
where
The slope of the linear equation is equal to
The y-coordinate of the y-intercept of the linear function is equal to
That means -------> This is the cost of the hot dog without topping
Hamburgers Stand
Let
C--------> total cost of the hamburger
x-------> is the number of toppings
we know that
where
The slope of the linear equation is equal to
The y-coordinate of the y-intercept of the linear function is equal to
That means -------> This is the cost of the hamburger without topping
therefore
<u>the answer is</u>
The linear equation of the hamburger cost is equal to