Move the decimal point in 250,000 to The left as many places as necessary to. Find a number that is greater than or equal to 1 a nd Less than 10
2 answers:
Your answer is 2.50 (And the rest of the 0s, but they aren't needed...) Since that is greater then 1, but less than 10.
Hello! To find the answer, you would have to move your decimal place 5 times to the left. When you do that, you get 2.5, which is greater than 1, but less than 10.
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Answer:
y = -5 + 6=1 is your answer
Answer:
N=2
Step-by-step explanation:
N=2
Answer:
Hey there!
3(2 - x) - 2(6x - 8)
6-3x-12x+16
6-15x+16
-15x+22
Hope this helps :)
Since this is a percentage, all you have to do is divide 21 from 80 and multiply that by 100
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![\sqrt{[(x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2}]}](https://tex.z-dn.net/?f=%5Csqrt%7B%5B%28x_%7B2%7D-x_%7B1%7D%29%5E%7B2%7D%2B%28y_%7B2%7D-y_%7B1%7D%29%5E%7B2%7D%5D%7D%20)
![\sqrt{[(3-(-4))^{2}+(-1-(-5))^{2}]}](https://tex.z-dn.net/?f=%5Csqrt%7B%5B%283-%28-4%29%29%5E%7B2%7D%2B%28-1-%28-5%29%29%5E%7B2%7D%5D%7D%20)
![\sqrt{[7^{2}+4^{2}]}](https://tex.z-dn.net/?f=%5Csqrt%7B%5B7%5E%7B2%7D%2B4%5E%7B2%7D%5D%7D%20)
![\sqrt{[49+16]}](https://tex.z-dn.net/?f=%5Csqrt%7B%5B49%2B16%5D%7D%20)
