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seraphim [82]
3 years ago
15

In september, seattle's daily high temperature has a mean of 70 °f and a standard deviation of 7 °f. What are the mean, standard

deviation, and variance in °c?
Mathematics
1 answer:
Anna [14]3 years ago
8 0
Mean= is the summation of the maximum temperatures ÷ the numbers of times the temperatures where recorded

standard deviation= is a number used to tell how measurements for a group are spread out from the average (mean), or expected value.

A low standard deviation means that most of the numbers are very close to the average.

A high standard deviation means that the numbers are spread out.

Variance= is a way to measure how far a set of numbers is spread out.

A variance of zero indicates that all of the data values are identical. All non-zero variances are positive.

A small variance indicates that the data points tend to be very close to the mean, and to each other.

A high variance indicates that the data points are very spread out from the mean, and from one another.
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Answer the photo please
alexandr402 [8]

Answer:

66.666666666667% error

Step-by-step explanation:

Percent Error = Vobserved - Vtrue / Vtrue

=  9 - 27 / 27

=  -18/27

= -66.666666666667%

= 66.666666666667% error

I hope this helps!

7 0
3 years ago
NEED HELP ASAP!!! What is the interquartile range of the data set? Enter the answer in the box. Key: 1|5 means 15 A stem-and-lea
monitta
To find the interquartile range, you will list the data that is presented in the stem and leaf plot.

Find the median of the data (30.5)

Find the median of the lower half and the median of the upper half.

Subtract these two values.

The data are <u>20</u>, 25, 30, 30, 31, 40, 41, <u>49</u>.
                            27.5                40.5
40.5-27.5 = 13

The interquartile range is 13.
3 0
3 years ago
Read 2 more answers
Which equation shows y=3/4x−52 in standard form? 4x−3y=10 4x−3y=−10 3x−4y=10 3x−4y=−10
snow_tiger [21]

Y = 3/4x - 5/2....subtract 3/4x from both sides
-3/4x + y = -5/2 ....multiply everything by common denominator of 4
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4 0
3 years ago
Rewrite \sqrt((1+cos45)/(2)) using a half-angle identity
aleksklad [387]

\stackrel{\textit{Half-Angle Identities}}{cos\left(\cfrac{\theta}{2}\right)=\pm \sqrt{\cfrac{1+cos(\theta)}{2}}} \\\\[-0.35em] ~\dotfill\\\\ \sqrt{\cfrac{1+cos(45^o)}{2}}~~ = ~~cos\left( \cfrac{45^o}{2} \right)\implies \sqrt{\cfrac{1+cos(45^o)}{2}}~~ = ~~cos(22.5^o)

7 0
1 year ago
If y varies directly as x, and y = 25 when x = 5, find y when x = 25.
zimovet [89]
A.125
Because to get from 5 to 25 you need to multiply by 5 so 25 times five equals 125
6 0
3 years ago
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