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seraphim [82]
4 years ago
15

In september, seattle's daily high temperature has a mean of 70 °f and a standard deviation of 7 °f. What are the mean, standard

deviation, and variance in °c?
Mathematics
1 answer:
Anna [14]4 years ago
8 0
Mean= is the summation of the maximum temperatures ÷ the numbers of times the temperatures where recorded

standard deviation= is a number used to tell how measurements for a group are spread out from the average (mean), or expected value.

A low standard deviation means that most of the numbers are very close to the average.

A high standard deviation means that the numbers are spread out.

Variance= is a way to measure how far a set of numbers is spread out.

A variance of zero indicates that all of the data values are identical. All non-zero variances are positive.

A small variance indicates that the data points tend to be very close to the mean, and to each other.

A high variance indicates that the data points are very spread out from the mean, and from one another.
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Step-by-step explanation:

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Which of the following is an example of a permutation?
N76 [4]

Permutation helps us to know the number of ways an object can be arranged in a particular manner. The correct option is D.

<h3>What are Permutation and Combination?</h3>

Permutation helps us to know the number of ways an object can be arranged in a particular manner. A permutation is denoted by 'P'.

The combination helps us to know the number of ways an object can be arranged without a particular manner. A combination is denoted by 'C'.

The example which is an example of permutation is Selecting a first-, second-, and third-place winner at baking.

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7 0
2 years ago
A surveyor standing on top of a cliff found that the angle of depression of a boat as sea is 22°. if the top of the cliff is 15m
Alex73 [517]

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From the photo above i interpreted the question and drew a triangle to make it easier to solve

Tan is used to solve the question as we were given opposite (as height of the cliff) and to find Adjacent ( the distance between the foot of the cliff to the boat)

Tan θ =Opp/Adj

Tan 22°=15/a

Cross Multiply

aTanθ=15°

Divide both sides by Tan 22

aTan22/Tan22 = 15/Tan 22

a = 15/Tan 22°

a = 37.13 m

Therefore the distance between the foot of the cliff to the boat is 37.13 metres

5 0
3 years ago
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