<em>Answer:</em>
<em />
<em>Step-by-step explanation:Let us find points of intersection of line </em>
<em>3
</em>
<em>x
</em>
<em>+
</em>
<em>4
</em>
<em>y
</em>
<em>−
</em>
<em>k
</em>
<em>=
</em>
<em>0
</em>
<em> and circle </em>
<em>x
</em>
<em>2
</em>
<em>+
</em>
<em>y
</em>
<em>2
</em>
<em>=
</em>
<em>16
</em>
<em>. We can do this by putting value of </em>
<em>y
</em>
<em> from first equation i.e. </em>
<em>y
</em>
<em>=
</em>
<em>k
</em>
<em>−
</em>
<em>3
</em>
<em>x
</em>
<em>4
</em>
<em> and we get
</em>
<em>
</em>
<em>x
</em>
<em>2
</em>
<em>+
</em>
<em>(
</em>
<em>k
</em>
<em>−
</em>
<em>3
</em>
<em>x
</em>
<em>)
</em>
<em>2
</em>
<em>16
</em>
<em>=
</em>
<em>16
</em>
<em>
</em>
<em>or </em>
<em>16
</em>
<em>x
</em>
<em>2
</em>
<em>+
</em>
<em>k
</em>
<em>2
</em>
<em>+
</em>
<em>9
</em>
<em>x
</em>
<em>2
</em>
<em>−
</em>
<em>6
</em>
<em>k
</em>
<em>x
</em>
<em>=
</em>
<em>256
</em>
<em>
</em>
<em>i.e. </em>
<em>25
</em>
<em>x
</em>
<em>2
</em>
<em>−
</em>
<em>6
</em>
<em>k
</em>
<em>x
</em>
<em>+
</em>
<em>k
</em>
<em>2
</em>
<em>−
</em>
<em>256
</em>
<em>=
</em>
<em>0
</em>
<em>
</em>
<em>This would give two values of </em>
<em>x
</em>
<em> and corresponding two values of </em>
<em>y
</em>
<em> i.e. two points. But tangent cuts the circle in only at one point. This will be so when discriminant is zero i.e.
</em>
<em>
</em>
<em>(
</em>
<em>−
</em>
<em>6
</em>
<em>k
</em>
<em>)
</em>
<em>2
</em>
<em>−
</em>
<em>4
</em>
<em>⋅
</em>
<em>25
</em>
<em>⋅
</em>
<em>(
</em>
<em>k
</em>
<em>2
</em>
<em>−
</em>
<em>256
</em>
<em>)
</em>
<em>=
</em>
<em>0
</em>
<em>
</em>
<em>or </em>
<em>−
</em>
<em>64
</em>
<em>k
</em>
<em>2
</em>
<em>+
</em>
<em>25600
</em>
<em>=
</em>
<em>0
</em>
<em> or </em>
<em>k
</em>
<em>=
</em>
<em>±
</em>
<em>20
</em>
<em>
</em>
<em>graph{(x^2+y^2-16)(3x+4y-20)(3x+4y+20)=0 [-10, 10, -5, 5]}</em>
5x-5=-7y
3x+2y=-8
First, you need to rearrange the first equation so it is in the same format as the second one.
5x-5=-7y
Add 5 to both sides
5x-5+5=-7y+5
Add 7y to both sides
5x+7y=-7y+7y+5
So you have 5x+7y=5
Now you need to multiply that equation by 3
3(5x+7y=5)
15x+21y=15
Multiply the second equation by -5
-5(3x+2y=-8)
-15x-10y=40
Now add them together
15x+21y=15
+(-15x-10y=40)
---------------------
11y=55
y=5
Now plug y=5 into one of the original equations and solve for x.
3x+2(5)=-8
3x+10=-8
3x=-8-10
3x=-18
x=-6
To check the solution plug them both into the other equation:
5(-6)-5=-7(5)
-30-5=-35
-35=-35
It checks.
Hope that helps.
False, dilation changes the base and height of the triangle, forcing the area to change as well.
