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Fynjy0 [20]
3 years ago
3

For a class project, students must select one topic from a list of 15 choices. They will also choose one presentation method: wr

itten report, oral presentation, or making a game. Use the Fundamental Counting Principle to determine how many different project combinations are possible. O A. 15 O B. 30 О С. 45 O D. 60
Mathematics
1 answer:
raketka [301]3 years ago
5 0

Answer: C. 45

Step-by-step explanation:

Given : Total number of choices of topics =15

Total choices of presentation methods= written report, oral presentation, or making a game.

Total number choices of presentation methods= 3

Now , by Fundamental Counting Principle , the number of different project combinations are possible would be

(choices of topics) x (choices of presentation methods)

(15) x (3)  =45

Therefore , the number of different project combinations are possible= 45

Hence, the correct option is C. 45 .

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Joan wants to reduce the area of her posters by one-third. Draw lines to match the original dimensions in the left column with t
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Answer:

1) 30\ in\ by\ 12\ in --------> 120\ in^{2}

2) 30\ in\ by\ 18\ in --------> 180\ in^{2}

3) 12\ in\ by\ 15\ in --------> 60\ in^{2}

4) 18\ in\ by\ 15\ in --------> 90\ in^{2}

Step-by-step explanation:

<u>Verify each case</u>

case 1) 30\ in\ by\ 12\ in

<em>Find the area with the original dimensions</em>

A=30(12)=360\ in^{2}

Reduce the area of the poster by one-third

360/3=120\ in^{2}

therefore

30\ in\ by\ 12\ in --------> 120\ in^{2}

case 2) 30\ in\ by\ 18\ in

<em>Find the area with the original dimensions</em>

A=30(18)=540\ in^{2}

Reduce the area of the poster by one-third

540/3=180\ in^{2}

therefore

30\ in\ by\ 18\ in --------> 180\ in^{2}

case 3) 12\ in\ by\ 15\ in

<em>Find the area with the original dimensions</em>

A=12(15)=180\ in^{2}

Reduce the area of the poster by one-third

180/3=60\ in^{2}

therefore

12\ in\ by\ 15\ in --------> 60\ in^{2}

case 4) 18\ in\ by\ 15\ in

<em>Find the area with the original dimensions</em>

A=18(15)=270\ in^{2}

Reduce the area of the poster by one-third

270/3=90\ in^{2}

therefore

18\ in\ by\ 15\ in --------> 90\ in^{2}

6 0
4 years ago
Find the area of the figure. area:__in2​
Goshia [24]

Answer:

200

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
Please help this is like the tenth time:(
DerKrebs [107]
Am not the best at math but 650.94 would be my answer.
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3 years ago
29% of base is 26.5 This is a question about percentage not triangles or geometry
ser-zykov [4K]

Answer:

Around 91.38

Step-by-step explanation:

26.5 x 100/29 = 91.38

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2 years ago
Can you please answer ASAP I need the answer
Alika [10]

Answer:

I think x=8

Step-by-step explanation:

5(x+7)+15=90

90 because it's a 90 degree angle

5x+35+15=90

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7 0
4 years ago
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