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DochEvi [55]
3 years ago
13

A user has a network device that streams media to the LAN. The device is visible on the network. All PCs on the LAN can ping the

device. All firewalls are turned off. The streaming device appears to function properly, but the media will not stream as requested. Which of the following TCP/IP technologies is not implemented properly?A. MulticastB. BroadcastsC. UnicastD. Anycast
Computers and Technology
1 answer:
trasher [3.6K]3 years ago
5 0

Answer: A. Multicast

Explanation:

Here we are given a situation where it is necessary for the device to stream media to all the PCs connected across the LAN. But as the they are unable to stream the media then it is a problem in the multicast TCP/Ip technology.

Multicasting enables to transfer information or messages from one to many or many to many. Here as a single device is responsible for streaming the content to other PCs across the LAN, therefore it is necessary that multicast has been properly implemented.

Option B is incorrect as it is not a scenario of broadcast as in broadcasting all the receivers must get the streaming however here if a PC does not want to receive the media stream it cannot receive for which multicasting is required.

Option C is incorrect as here we are not talking of one to one communication.

Option D is incorrect as here we cannot have more than one route to send the media content except the LAN.

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Answer:

In Python:

side1 = float(input("Side 1: "))

side2 = float(input("Side 2: "))

side3 = float(input("Side 3: "))

if side1>0 and side2>0 and side3>0:

   if side1+side2>=side3 and side2+side3>=side1 and side3+side1>=side2:

       if side1 == side2 == side3:

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       elif side1 == side2 or side1 == side3 or side2 == side3:

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       else:

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   else:

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else:

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Explanation:

The next three lines get the input of the sides of the triangle

<em>side1 = float(input("Side 1: ")) </em>

<em>side2 = float(input("Side 2: ")) </em>

<em>side3 = float(input("Side 3: ")) </em>

If all sides are positive

if side1>0 and side2>0 and side3>0:

Check if the sides are valid using the following condition

   if side1+side2>=side3 and side2+side3>=side1 and side3+side1>=side2:

Check if the triangle is equilateral

<em>        if side1 == side2 == side3: </em>

<em>            print("Equilateral Triangle") </em>

Check if the triangle is isosceles

<em>        elif side1 == side2 or side1 == side3 or side2 == side3: </em>

<em>            print("Isosceles Triangle") </em>

Otherwise, it is scalene

<em>        else: </em>

<em>            print("Scalene Triangle") </em>

Print invalid, if the sides do not make a valid triangle

<em>    else: </em>

<em>        print("Invalid Triangle") </em>

Print invalid, if the any of the sides are negative

<em>else: </em>

<em>    print("Invalid Triangle")</em>

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