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Andreyy89
3 years ago
8

So i'm trying to figure out why this code wont run can anyone help me

Computers and Technology
1 answer:
MaRussiya [10]3 years ago
8 0

Answer:

<em><u>use</u></em><em><u> </u></em><em><u>the</u></em><em><u> </u></em><em><u>ope</u></em><em><u>ning</u></em><em><u> </u></em><em><u>and</u></em><em><u> </u></em><em><u>cl</u></em><em><u>osing</u></em><em><u> </u></em><em><u>tags</u></em><em><u> </u></em>

<em><u>[</u></em><em><u>Tex]</u></em><em><u> </u></em><em><u>[</u></em><em><u>\</u></em><em><u>t</u></em><em><u>e</u></em><em><u>x</u></em><em><u>]</u></em><em><u> </u></em><em><u>ok</u></em>

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Develop a CPP program to test is an array conforms heap ordered binary tree. This program read data from cin (console) and gives
mafiozo [28]

Answer:

Following are the code to this question:

#include<iostream>//import header file

using namespace std;

int main()//defining main method

{

int ar[7];//defining 1_D array that stores value      

int i,x=0,l1=1,j; //defining integer variable

for(i=0;i<7;i++)//defining for loop for input value from user ends  

{

cout<<"Enter a Number: ";//print message

cin>>ar[i];//input value in array

if(l1<=2 && i>0)//using if block that checks the array values  

{

x++;//increment the value of x by 1  

}

if(l1>2 && i>0)//using if block that checks the array values  

{

l1=l1-2;//using l1 variable that decrases the l1 value by 2  

}

j=i-x;//using j variable that holds the index of the root of the subtree

if(i>0 && ar[j]>ar[i])// use if block that checks heap condition  

{

l1++; //increment the value of l1 variable

}

if(i>0 && ar[j]<ar[i])// using the if block that violate the heap rule  

{

cout<<ar[i]<<" "<<"Violate the heap";//print message with value

break;//using break keyword  

}

}

return 0;

}

Output:

1)

Enter a Number: -15

Enter a Number: -5

-5 Violate the heap

2)

Enter a Number: 45

Enter a Number: 0

Enter a Number: 55

55 Violate the heap

Explanation:

  • In the above-given C++ language code, an array "ar" and other integer variables " i,x,l1, j" is declared, in which "i" variable used in the loop for input values from the user end.
  • In this loop two, if block is defined, that checks the array values and in the first, if the block it will increment the value of x, and in the second if the block, it will decrease the l1 value by 2.
  • In the next step, j variable is used that is the index of the root of the subtree. In the next step, another if block is used, that checks heap condition, that increment the value of l1 variable. In the, if block it violate the heap rule and print its values.
5 0
3 years ago
Which function prompts the user to enter information?
Rzqust [24]

Answer:

input() prompts the user to enter information

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3 years ago
Read 2 more answers
Why is there no window on dishwsher
olchik [2.2K]

Because most people really don't want or need to see what's in there.

If you want to, open the door during the cycle. It won't harm anything.

If you're curious to see a dishwasher in action, some appliance showrooms have a display model, where the spray parts and the racks are in an entirely transparent box. They're to show how powerfully and completely the stuff inside will get cleaned, but you can also see how the dishwasher is intended to work, by filling with just a couple of inches of water, and then recirculating it for the duration of the cycle, to loosen the stuff on the dishes.

3 0
2 years ago
Read 2 more answers
I got a 52 on my test :(
Eduardwww [97]

Answer:

that sucks i hope u can do better next time have a good day

Explanation:

7 0
3 years ago
create your own min function that finds the minimum element in a list and use it in a separate function
schepotkina [342]

Answer:

def minfunction(mylist):

   min = mylist[0]

   for i in mylist:

       if i < min:

           min = i

   print("The minimum is: "+str(min))

   

def anotherfunction():

   mylist = []

   n = int(input("Length of list: "))

   for i in range(n):

       listelement = int(input(": "))

       mylist.append(listelement)

   minfunction(mylist)

   

anotherfunction()

Explanation:

This solution is implemented in Python

This defines the min function

def minfunction(mylist):

This initializes the minimum element to the first index element

   min = mylist[0]

This iterates through the list

   for i in mylist:

This checks for the minimum

       if i < min:

... and assigns the minimum to variable min

           min = i

This prints the minimum element

   print("The minimum is: "+str(min))

   

This defines a separate function. This  separate function is used to input items into the list

def anotherfunction():

This defines an empty list

   mylist = []

This prompts user for length of list

   n = int(input("Length of list: "))

The following iteration inputs elements into the list

<em>    for i in range(n):</em>

<em>        listelement = int(input(": "))</em>

<em>        mylist.append(listelement)</em>

This calls the minimum function

   minfunction(mylist)

   

The main starts here and this calls the separate function

anotherfunction()

5 0
3 years ago
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