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Andre45 [30]
3 years ago
5

Which of the following is not an equation of a simple, even polynomial function? (Select all to apply.)

Mathematics
2 answers:
Ne4ueva [31]3 years ago
4 0

Wouldn't it be y = | x |? I am not 100% positive but I'm pretty sure that you need to have a least one value. Again not 100% sure

Marina CMI [18]3 years ago
4 0

Answer:

y=x^3

Step-by-step explanation:

A function is an even polynomial function when f(-x) is equal to f(x)

Lets check each option, replace x with -x and see whether we get same y equation

y=|x|, Replace x with -x

y=|-x|=x, for any x value the value of y is positive always. So it is an even function

y=x^2

y=(-x)^2=x^2 same as the given equation . So it is an even function

y=x^3

y=(-x)^3=-x^3 It is not same as the given equation . So it is not an even function

y=-x^2

y=-(-x)^2=-x^2 same as the given equation . So it is an even function

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Answer:

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Step-by-step explanation:

A) A distance time graph as seen in the attachment provides a representation of the distance travelled.

We are told the car travels at a constant speed of 100 meters per 4 seconds. Which means that 100 m for each 4 hours. So, for 200m, it's 8 hours like seen in the graph and for 300m,it's 12 hours as seen in the graph.

B) And expression for the distance is;

d = vt

Where;

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v is speed in m/s and t is time

We are told that the car travels at a constant speed of 100 meters per 4 seconds.

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Distance travelled over time is;

d(t) = 25t

C) Looking at both A and B above, it's obvious that the expression of the distance shows a more clearer way of getting the distance because once we know the time travelled, we will just plug it into the equation and get the distance. Whereas, for the representation form, one will need to longer graphs if the time spent is very long.

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3 years ago
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5 0
3 years ago
Evaluate the expression 3(7 + 4)2 − 14 ÷ 7. (5 points)
Kitty [74]
<span>3(7 + 4)2 − 14 ÷ 7

First do the parenthesis

7 + 4 = 11

so the question looks like: 3(11)2 - 14/7

Then multiply 3, 11, and 2 together

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Then just simplify

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8 0
4 years ago
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