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2 years ago

What’s the equation?

Mathematics

1 answer:

slega [8]2 years ago

8 0

Answer:

The equation is;

y = 2x^2 -8x + 12

Step-by-step explanation:

The vertex form can be written as;

a(x-h)^2 + k

(h,k) represents the coordinates of the vertex

In this case, we have this as (2,4)

The value of a is positive as the parabola opens up and it is the axis of symmetry

It is the x value that divides the graph into 2

Thus, we have x as = 2

so the equation of the graph will be;

2(x-2)^2 + 4

2(x^2 - 4x + 4) + 4

= 2x^2 -8x + 8 + 4

= 2x^2 -8x + 12

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andrezito [222]

if you are driving 40 miles per hour

1 hour = 40 miles

60-40 = 20 miles left

20/40 = 0.5

1+0.5 = 1.5 total hours

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2 years ago

What is the probability that a value falls in the interval μ ± 2σ, that computes the probability P(-2 < Z < 2). Round to f

bija089 [108]

Answer:

0.9544

Step-by-step explanation:

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2 years ago

A tank contains 1600 L of pure water. Solution that contains 0.04 kg of sugar per liter enters the tank at the rate 2 L/min, and

goldfiish [28.3K]

Let S(t) denote the amount of sugar in the tank at time t. Sugar flows in at a rate of

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and flows out at a rate of

(S(t)/1600 kg/L) * (2 L/min) = S(t)/800 kg/min

Then the net flow rate is governed by the differential equation

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Solve for S(t):

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The left side is the derivative of a product:

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Integrate both sides:

$e^{t/800}S(t)=\displaystyle\frac8{100}\int e^{t/800}\,\mathrm dt$

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$S(t)=64+Ce^{-t/800}$

There's no sugar in the water at the start, so (a) S(0) = 0, which gives

$0=64+C\impleis C=-64$

and so (b) the amount of sugar in the tank at time t is

$S(t)=64\left(1-e^{-t/800}\right)$

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3 years ago

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Hii I hope this helps! :)
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3 years ago

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