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3 years ago

What’s the equation?

Mathematics

1 answer:

slega [8]3 years ago

8 0

Answer:

The equation is;

y = 2x^2 -8x + 12

Step-by-step explanation:

The vertex form can be written as;

a(x-h)^2 + k

(h,k) represents the coordinates of the vertex

In this case, we have this as (2,4)

The value of a is positive as the parabola opens up and it is the axis of symmetry

It is the x value that divides the graph into 2

Thus, we have x as = 2

so the equation of the graph will be;

2(x-2)^2 + 4

2(x^2 - 4x + 4) + 4

= 2x^2 -8x + 8 + 4

= 2x^2 -8x + 12

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A bird drops a nut from a height of 441 feet. Its height, h, in feet is given by the equation h=-16t^2=441 where t is the time i

Ahat [919]

<span> A bird drops a nut from a height of 441 feet.
Its height, h, in feet is given by the equation h=-16t^2=441
,where t is the time in seconds the nut has fallen.

The time it </span>will it take for the nut to hit the ground is given as:

$t^{2} = \frac{441}{16} \\ \\ t = \frac{21}{4} \\ \\ t = 5.25 seconds$

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3 years ago

Draw ando label a number line beginning at 1 and ending at 2 that has been partitioned into sixth sense.

SCORPION-xisa [38]

Steps:
1. Draw a number line and put the numbers 1 and 2. (Do not put the numbers very close together)

2. Between 1 and 2 put 1/6, 2/6, 3/6, 4/6, 5,6, and 6/6. If they wanted it into seventh sense then you would do the same thing but split it into 7.

*I will send you a pic of what I mean

5 0

3 years ago

The position function of a particle in rectilinear motion is given by s(t) = 2t3 – 21t2 + 60t + 3 for t ≥ 0 with t measured in s

Norma-Jean [14]

The positions when the particle reverses direction are:

$s(t_1)=55ft\\\\s(t_2)=28ft$

The acceleraton of the paticle when reverses direction is:

$a(t_1)=-18\frac{ft}{s^{2}}\\ \\a(t_2)=a(5s)=18\frac{ft}{s^{2}}$

Why?

To solve the problem, we need to remember that if we derivate the position function, we will get the velocity function, and if we derivate the velocity function, we will get the acceleration function. So, we will need to derivate two times.

Also, when the particle reverses its direction, the velocity is equal to 0.

We are given the following function:

$s(t)=2t^{3}-21t^{2}+60t+3$

So,

- Derivating to get the velocity function, we have:

$v(t)=\frac{ds}{dt}=(2t^{3}-21t^{2}+60t+3)\\\\v(t)=3*2t^{2}-2*21t+60*1+0\\\\v(t)=6t^{2}-42t+60$

Now, making the function equal to 0, to find the times when the particle reversed its direction, we have:

$v(t)=6t^{2}-42t+60\\\\0=6t^{2}-42t+60\\\\0=t^{2}-7t+10\\(t-5)*(t-2)=0\\\\t_{1}=5s\\t_{2}=2s$

We know that the particle reversed its direction two times.

- Derivating the velocity function to find the acceleration function, we have:

$a(t)=\frac{dv}{dt}=6t^{2}-42t+60\\\\a(t)=12t-42$

Now, substituting the times to calculate the accelerations, we have:

$a(t_1)=a(2s)=12*2-42=-18\frac{ft}{s^{2}}\\ \\a(t_2)=a(5s)=12*5-42=18\frac{ft}{s^{2}}$

Now, substitutitng the times to calculate the positions, we have:

$s(t_1)=2*(2)^{3}-21*(2)^{2}+60*2+3=16-84+120+3=55ft\\\\s(t_2)=2*(5)^{3}-21*(5)^{2}+60*5+3=250-525+300+3=28ft$

Have a nice day!

3 0

3 years ago

Rate of change of d=60h + 20

77julia77 [94]

H=1/3+1/60d,d=R Hope this is correct.

6 0

3 years ago

PLS HELP MEEEEE REEEEEEE

JulsSmile [24]

Answer:

$954.78

Step-by-step explanation:

Since it increases by 8.5%, all you have to do is multiply 879.98 by 1.085.

879.98 * 1.085 = $954.7783 = $954.78 (you always have to round to two decimal places with money)

5 0

2 years ago