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3 years ago

What is the slope-intercept equation for this

Mathematics

1 answer:

ZanzabumX [31]3 years ago

3 0

Answer:

Y = 2x - 4

Slope is 2.

Y-intercept is -4.

Step-by-step explanation:

To find slope in standard form, take -A/B. So 6 is A, -3 is B. -(6/-3) = 2.

And to find the y-int, take C/B. C is 12. So, 12/-3 = -4.

Or you could also rearrange the equation. . .

6x - 3y = 12.
Subtract 6 from both sides.
-3y = -6x + 12
Divide by -3 to isolate the y.
y = 2x - 4.

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The inside wheels of a car traveling on a circular path are rotating half as fast as the outside wheels. The front two wheels ar

barxatty [35]

Answer:

about 37.7 feet

Step-by-step explanation:

If the outside wheels are turning twice as fast, they go twice the distance in the same time. The distance they travel is proportional to the radius of the circle, so the outside circle must have twice the radius of the inside circle.

Adding 6 ft to the radius of the inside circle doubles the radius, so the inside circle's radius must be 6 feet. Then the circumference of the inside circle is ...

C = 2πr = 2π(6 ft) = 12π ft ≈ 37.7 ft

5 0

3 years ago

Which line contains the pint (6-4) and has a slope of -5/6

natima [27]

Answer:

y = - 5/6 x + 1

Step-by-step explanation:

y = mx + b m: slope b: y intercept

point (6 , -4) x = 6 y = -4

b = y - mx = -4 - ((-5/6) x 6) = - 4 + 5 = 1

equation: y = - 5/6 x + 1

7 0

3 years ago

Topic: The Quadratic Formula

Finger [1]

Answer:

Step-by-step explanation:

The quadratic formula for a equation of form

ax²+bx + c = 0 is

$x= \frac{-b +- \sqrt{b^2-4ac} }{2a}$

For the first equation,

x²+3x-4=0,

we can match that up with the form

ax²+bx + c = 0

to get that

ax² = x²

divide both sides by x²

a=1

3x = bx

divide both sides by x

3 = b

-4 = c

. We can match this up because no constant multiplied by x could equal x² and no constant multiplied by another constant could equal x, so corresponding terms must match up.

Plugging our values into the equation, we get

$x= \frac{-3 +- \sqrt{3^2-4(1)(-4)} }{2(1)} \\= \frac{-3+-\sqrt{25} }{2} \\ = \frac{-3+-5}{2} \\= -8/2 or 2/2\\= -4 or 1$

as our possible solutions

Plugging our values back into the equation, x²+3x-4=0, we see that both f(-4) and f(1) are equal to 0. Therefore, this has 2 real solutions.

Next, we have

x²+3x+4=0

Matching coefficients up, we can see that a = 1, b=3, and c=4. The quadratic equation is thus

$x= \frac{-3 +- \sqrt{3^2-4(1)(4)} }{2(1)}\\= \frac{-3 +- \sqrt{9-16} }{2}\\= \frac{-3 +- \sqrt{-7} }{2}\\$

Because √-7 is not a real number, this has no real solutions. However,

(-3 + √-7)/2 and (-3 - √-7)/2 are both possible complex solutions, so this has two complex solutions

Finally, for

4x² + 1= 4x,

we can start by subtracting 4x from both sides to maintain the desired form, resulting in

4x²-4x+1=0

Then, a=4, b=-4, and c=1, making our equation

$x=\frac{-(-4) +- \sqrt{(-4)^2-4(4)(1)} }{2(4)} \\= \frac{4+-\sqrt{16-16} }{8} \\= \frac{4+-0}{8} \\= 1/2$

Plugging 1/2 into 4x²+1=4x, this works as the only solution. This equation has one real solution

7 0

2 years ago

will the opposite of a number always,sometimes,or never be greater than the number itself??????? can someone do an example and a

weeeeeb [17]

When the number is positive, its opposite is less than the number.

9 ==> -9 . . . . . . less
72 ==> -72 . . . . less
324 ==> -324 . . less

When the number is negative, its opposite is greater than the number.

-8 ==> 8 . . . . . . greater
-3/4 ==> 3/4 . . . greater
-429 ==> 429 . . greater .

We've seen that the opposite can be less, and it can also be greater.
I guess that means that it's sometimes greater.

8 0

2 years ago

Read 2 more answers

What is 1/5 divided by 1/2

Len [333]

The answer to your question is 0.1

4 0

2 years ago

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