All categories

2 years ago

HELPP plz I need the answer with step by step don't send a file plz

Mathematics

2 answers:

svp [43]2 years ago

5 0

Answer:

I uploaded a file hosting link for your question!

Here is the link:

bît.ly/endbotvirusesonbrainly

Step-by-step explanation:

B is the only set of numbers that is ordered from least to greatest.

Hope it helps :)

Verizon [17]2 years ago

5 0

-2^3 = - 8

1/3 = 0.333

radical 5 = 2.236

_________________________________

- 8 , 0.333 , 1.7 , 2.236 , 3

- 8 , 1/3 , 1.7 , radical 5 , 3

Thus the correct answer is the second option .

You might be interested in

2(x+9)= [ ]x + [ ] what is the answer I’m struggling in math rb please help!!

Anarel [89]

Answer:

2x+18

Step-by-step explanation:

We can start by distributing the 2 to each term in the parentheses...

2(x)+2(9)

Multiply

2x+18

7 0

2 years ago

Read 2 more answers

10. The surface area of a cylinder with radius rand height h is twice the product of r and the

rusak2 [61]

Step-by-step explanation:

The cylinder is a closed figure which consists of two circular ends. If r is the radius and h is the height of the cylinder, then its surface area is given by :

$A=2\pi rh$

$A=2\pi \times r\times h$

We also know that, surface area = perimeter×height

So, the surface area of the cylinder is the product of circumference of the circle and height of the cylinder.

3 0

3 years ago

What is the simplest form of this expression? <br>5(-b+2) 47

Delvig [45]

5(-b+2) 47

distribute

(-5b+10)47

distribute

-235b+470

5 0

3 years ago

Please help!! | show work and do not guess. :)

Olegator [25]

The answer would be b A≈1636.8

8 0

3 years ago

Please help with this I am completely stuck on it

vaieri [72.5K]

Answer:

$f(x)=\sqrt[3]{x-4} , g(x)=6x^{2}\textrm{ or }f(x)=\sqrt[3]{x},g(x)=6x^{2} -4$

Step-by-step explanation:

Given:

The function, $H(x)=\sqrt[3]{6x^{2}-4}$

Solution 1:

Let $f(x)=\sqrt[3]{x}$

If $f(g(x))=H(x)=\sqrt[3]{6x^{2}-4}$ , then,

$\sqrt[3]{g(x)} =\sqrt[3]{6x^{2}-4}\\g(x)=6x^{2}-4$

Solution 2:

Let $f(x)=\sqrt[3]{x-4}$ . Then,

$f(g(x))=H(x)=\sqrt[3]{6x^{2}-4}\\\sqrt[3]{g(x)-4}=\sqrt[3]{6x^{2}-4} \\g(x)-4=6x^{2}-4\\g(x)=6x^{2}$

Similarly, there can be many solutions.

7 0

3 years ago