It's 78π inches so probably d.
Answer:
In order from least to greatest: 0.25, 3 ⅜, 3 <span>⅖</span>;
Or, write as: 0.25 < 3 ⅜ < 3 ⅖ .
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Explanation:
0.25 = ¼ l (less than "1"); the lowest of the three given values.
The remaining two values have the same whole number of 3, and a fraction:
3 <span>⅖ ;</span> and 3 ⅜.
The least common multiples among the denominators of the fraction values is 40. ⅖ = ?/40 ; 5*? =40? 5* 8 = 40, so 2*8 = 16;
Thus, ⅖ = 16/40, and 3 ⅖ = 3 16/40. 3/8 = ?/40? 8*5 =40; so 3*5 = 15 ; thus ⅜ = 15/40; and
and 3 ⅜ = 3 15/40.
3 15/40 is less than than 3 16/40;
as such; 3 ⅜ is less than 3 ⅖.
So, in order from least to greatest: 0.25, 3 ⅜, 3 ⅖;
Or, write as: 0.25 < 3 ⅜ < 3 ⅖ .
Answer:
Step-by-step explanation:
given are four statements and we have to find whether true or false.
.1 If two matrices are equivalent, then one can be transformed into the other with a sequence of elementary row operations.
True
2.Different sequences of row operations can lead to different echelon forms for the same matrix.
True in whatever way we do the reduced form would be equivalent matrices
3.Different sequences of row operations can lead to different reduced echelon forms for the same matrix.
False the resulting matrices would be equivalent.
4.If a linear system has four equations and seven variables, then it must have infinitely many solutions.
True, because variables are more than equations. So parametric solutions infinite only is possible
Answer:
A) See the picture
B) 14
C) 45%
Step-by-step explanation:
A) To create a histogram like the one on the picture you can use an online tool like socscistatistics where the number of classes is customizable
B) Because the question B and C have to be responded using a frequency table with 8 classes the answer is 14; the method of using cumulative frequency tables should only be considered as a way of estimation, that is because you obtain values that depend on your choice of class intervals. The way to get a better answer would be to use all the scores in the distribution
Pc1 = 100*(4/40) = 10
Pc2 = 100*(4/40) = 10
Pc3 = 100*(3/40) = 7.5
Pc4 = 100*(11/40) = 27.5
Pc5 = 100*(5/40) = 12.5
Pc6 = 100*(4/40) = 10
Pc7 = 100*(7/40) = 17.5
Pc8 = 100*(2/40) = 5
Pc8 + Pc7 + Pc6 + Pc5 + Pc4 + Pc3 + Pc2 = 90%
Therefore, From class 8 to class 2 is the top 90% of the applicants and the minimum score is 14.
C) Scores equal to or greater than 20 are from class 8 to class 5
Pc8 + Pc7 + Pc6 + Pc5 = 45%
Answer:
Step-by-step explanation:
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