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3 years ago

25-20x+4x² heh help pls and hurry :((

2 answers:

8 0

Answer:100 POINTS! (50 split up) PLSSSSSSSSSS HELP!!! I REALLY NEED IT SO MUCH :( I PROMICE TO GIVE BRAINLIEST AND FIVE STARS AND A THANKS! 6TH GRADE SCIENCE! i used all my points for this!

You measure the mass of an apple using a balance. You get these three measurements:

100

yulyashka [42]3 years ago

6 0

25- 20x + 4x^2
=4x^2 - 20x + 25
=4x^2 - x(10+10) +25
=4x^2 - 10x - 10x + 25
=2x(2x - 5) - 5( 2x - 5)
=(2x - 5)(2x - 5)
=(2x - 5)^2

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Solve this quadratic equation by completing the square.

erastova [34]

Answer:

Step-by-step explanation:

x² + 6x = 18

To complete the square, take the coefficient of the x term, halve it, square the result, then add to both sides.

(6/2)² = 3² = 9

x² + 6x + 9 = 18 + 9

(x + 3)² = 27

x + 3 = ±√27

x = -3 ± √27

5 0

3 years ago

The function f(x) = 5One-fifth is reflected over the y-axis. Which equations represent the reflected function? Select two option

postnew [5]

Answer:

The equations that represent the reflected function are

$f(x)=5(\frac{1}{5})^{-x}$

$f(x)=5(5)^{x}$

Step-by-step explanation:

The correct question in the attached figure

we have the function

$f(x)=5(\frac{1}{5})^{x}$

we know that

A reflection across the y-axis interchanges positive x-values with negative x-values, swapping x and −x.

therefore

$f(−x) = f(x).$

The reflection of the given function across the y-axis will be equal to

(Remember interchanges positive x-values with negative x-values)

$f(x)=5(\frac{1}{5})^{-x}$

An equivalent form will be

$f(x)=5(\frac{1}{5})^{(-1)(x)}=5[(\frac{1}{5})^{-1})]^{x}=5(5)^{x}$

therefore

The equations that represent the reflected function are

$f(x)=5(\frac{1}{5})^{-x}$

$f(x)=5(5)^{x}$

9 0

3 years ago

Read 2 more answers

X + 5y = 28 2x + 3y = 21 Solve for x and y.

snow_tiger [21]

First what we gonna do is solve for y.
x+5y=28 Subtract 5y both sides.
-5y -5y
x=-5y+28 Then you have to replace x with the equation.
2(-5y+28)+3y=21 Multiply.
-10y+56+3y=21 Combine like terms and subtract 56 both sides.
-56 -56
-7y=-35 Divide -7 both sides.
y=5 Simplify.
x=-5(5)+28 Multiply and add.
x=-25+28
x=3
Heres your answer x=3 and y=5.

6 0

3 years ago

The time for this event for boys in secondary school is known to possess a normal distribution with a mean of 460 seconds and a

AlekseyPX

Answer:

The time that the boys need to beat in order to earn a certificate of recognition from the fitness association is 511.264 seconds.

Step-by-step explanation:

We are given that the time for this event for boys in secondary school is known to possess a normal distribution with a mean of 460 seconds and a standard deviation of 40 seconds.

The fitness association wants to recognize the fastest 10% of the boys with certificates of recognition.

Let X = time for this event for boys in secondary school

SO, X ~ Normal( $\mu=460,\sigma^{2} =40^{2}$ )

The z-score probability distribution for normal distribution is given by;

Z = $\frac{X-\mu}{\sigma}$ ~ N(0,1)

where, $\mu$ = mean time = 460 seconds

$\sigma$ = standard deviation = 40 seconds

The Z-score measures how many standard deviations the measure is away from the mean. After finding the Z-score, we look at the z-score table and find the p-value (area) associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X.

Now, it is given that the fitness association wants to recognize the fastest 10% of the boys with certificates of recognition, which means;

P(X > x) = 0.10 {where x is the required time which boy need to beat}

P( $\frac{X-\mu}{\sigma}$ > $\frac{x-460}{40}$ ) = 0.10

P(Z > $\frac{x-460}{40}$ ) = 0.10

So, the critical value of x in the z table which represents the top 10% of the area is given as 1.2816, that is;

$\frac{x-460}{40} =1.2816$

${x-460}{} =1.2816\times 40$

$x$ = 460 + 51.264 = 511.264 seconds

Hence, the time that the boys need to beat in order to earn a certificate of recognition from the fitness association is 511.264 seconds.

8 0

3 years ago

Una persona asegura que su casa tiene forma rectangular y que el perímetro de la misma es de 18 m y que además, su área es de 21

leva [86]

Considerando las fórmulas para el perímetro y el área de un rectángulo, hay que se chega en una eccuación cuadrática sin solución, o sea, las medidas no son posibles y la persona estaba mintiendo.

<h3>¿Cuál es la fórmula para el perímetro y el área de un rectángulo?</h3>

Considerando que las dimensiones son l y w, hay que:

El perímetro es: P = 2(l + w).

El área es: A = lw.

El perímetro es de 18 m, o sea:

2(l + w) = 18

l + w = 9

l = 9- w.

El área es de 21 m², o sea:

lw = 21

(9- w)w = 21

-w² + 9 - 21 = 0

w² - 9w + 21 = 0

El discriminante es dado por:

D = 9² - 4 x 1 x 21 = -3.

El discriminante negativo implica que la eccuación cuadrática no tiene solución, o sea, las medidas no son posibles y la persona estaba mintiendo.

Puede-se aprender más a cerca de el perímetro y el área de un rectángulo en brainly.com/question/26475963

#SPJ1

4 0

2 years ago