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Amanda [17]
3 years ago
14

What is the center and radius of a given circle (x+3)^2+(y-4)^2= 25

Mathematics
1 answer:
Fantom [35]3 years ago
4 0

The general form for a circle centered at (a,b) with radius r is

(x - a)² + (y - b)² = r²

Comparing to our form we have a = -3, b=4, r²=25 so r=5

Answer: Center (-3,4) radius 5

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I will give brainliest if correct
dalvyx [7]

Answer:supplementary

Step-by-step explanation:

Opposite angles in any quadrilateral inscribed in a circle are supplements of each other.

5 0
3 years ago
What is a counterexample for the statement the difference between two integers is always positive
Maru [420]

We have to give counter example for the given statement:

"The difference between two integers is always positive"

This statement is not true. As integers is the set of numbers which includes positive and as well as negative numbers including zero.

Consider any two integers say '2' and '-8'. Now, let us consider the difference between these two integers.

So, 2 - 8

= -6 which is not positive.

Therefore, it is not necessary that the difference of two integers is only positive. The difference of two integers can be positive, negative or zero.

3 0
3 years ago
A high school club has a performance, with 800 tickets to sell. Tickets are $6 before the day of the show, and $9 on the day of
sweet-ann [11.9K]
A) Let x = number of presale tickets 
<span>y = number of day of show tickets </span>

<span>x + y =< 800 </span>
<span>6x + 9y >= 5000 </span>

<span>b) 6x + 9y >=5000 </span>
<span>6(440) + 9y >=5000 </span>

<span>y >= 262.2 </span>
<span>263 tickets </span>

<span>440 advance purchase tickets added to 263 day of show tickets is 703 tickets, which is below the 800 ticket maximum.</span>
4 0
3 years ago
Read 2 more answers
Both circle Q and circle R have a central angle measuring 140°. The area of circle Q's sector is 25π m2, and the area of circle
taurus [48]

Solution:

we are given that

Both circle Q and circle R have a central angle measuring 140°. The area of circle Q's sector is 25π m^2, and the area of circle R's sector is 49π m^2.

we have been asked to find the ratio of the radius of circle Q to the radius of circle R?

As we know that

Area of the sector is directly proportional to square of radius. So we can write

Area  \  \   \alpha \ \  r^2\\ \\ \Rightarrow A=kr^2\\ \\ \text{where k is some proportionality constant }\\ \\ \Rightarrow \frac{A_1}{A_2}=\frac{r_1^2}{r_2^2}\\ \\  \Rightarrow \frac{r_1^2}{r_2^2}=\frac{A_1}{A_2}\\ \\  \Rightarrow \frac{r_1^2}{r_2^2}=\frac{25 \pi}{49 \pi}\\ \\  \Rightarrow \frac{r_1}{r_2}=\sqrt{\frac{25 \pi}{49 \pi}} \\ \\  \Rightarrow \frac{r_1}{r_2}=\frac{5}{7} \\


7 0
4 years ago
Read 2 more answers
Solve the system of equations of equations by graphing on your calculator rounded to 3 decimal spaces
Vanyuwa [196]

Answer:

x=2.333\\y=-1,667  

Step-by-step explanation:

we have

y-x=-4 ----> equation A

2x+y=3 ----> equation B

Solve the system of equations by graphing

Remember that the solution of the system is the intersection point both graphs

Using a graphing tool

The intersection point is (2.333,-1.667)

see the attached figure

therefore

The solution is

x=2.333\\y=-1,667        

3 0
3 years ago
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