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miv72 [106K]
4 years ago
12

A mixture of helium and neon gases has a density of 0.2460 g/L at 35.2°C and 288 torr. What is the mole fraction of neon in this

mixture?
Chemistry
1 answer:
pshichka [43]4 years ago
6 0
We know the volume of one mole of gas at 273 K and 760 Torr is 22.4 L. Using
(PV)/T = constant
We can calculate the volume of the gasses at the given conditions:
(P₁V₁)/T₁ = (P₂V₂)/T₂
(760 * 22.4) / 273 = (288 V₂) / 308.2
V₂ = 66.7 L
Mass of He: 4
Mass of Ne: 20
Fraction of Ne: x
Fraction of He: 1 - x
avg density = (∑(component fraction × component mass))/volume
0.2460 = (20x + 4(1 - x))/ 66.7
x = 0.775
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