Answer:
SEE THE FOLLOWING PICTURE FOR THE QUESTION AND....GOOD ONE
Explanation:
Answer : The speed in miles per hour is 22 mile/hr.
The speed in yard per min is 26617.8 yard/min
Explanation :
The conversion used for meters to miles is:
![1m=100cm\times \frac{1in}{2.54cm}\times \frac{1ft}{12in}\times \frac{1mile}{5280ft}](https://tex.z-dn.net/?f=1m%3D100cm%5Ctimes%20%5Cfrac%7B1in%7D%7B2.54cm%7D%5Ctimes%20%5Cfrac%7B1ft%7D%7B12in%7D%5Ctimes%20%5Cfrac%7B1mile%7D%7B5280ft%7D)
The conversion used for second to hour is:
![1s=\frac{1}{60}min\times \frac{1hr}{60min}](https://tex.z-dn.net/?f=1s%3D%5Cfrac%7B1%7D%7B60%7Dmin%5Ctimes%20%5Cfrac%7B1hr%7D%7B60min%7D)
The conversion used for meter per second to mile per hour is:
![1\frac{m}{s}=\frac{100cm\times \frac{1in}{2.54cm}\times \frac{1ft}{12in}\times \frac{1mile}{5280ft}}{\frac{1}{60}min\times \frac{1hr}{60min}}](https://tex.z-dn.net/?f=1%5Cfrac%7Bm%7D%7Bs%7D%3D%5Cfrac%7B100cm%5Ctimes%20%5Cfrac%7B1in%7D%7B2.54cm%7D%5Ctimes%20%5Cfrac%7B1ft%7D%7B12in%7D%5Ctimes%20%5Cfrac%7B1mile%7D%7B5280ft%7D%7D%7B%5Cfrac%7B1%7D%7B60%7Dmin%5Ctimes%20%5Cfrac%7B1hr%7D%7B60min%7D%7D)
As we are given the speed of 407.0 meter per second. Now we have to determine the speed in miles per hour.
![1m/s=2.2mile/hr](https://tex.z-dn.net/?f=1m%2Fs%3D2.2mile%2Fhr)
So, ![407.0m/s=\frac{2.2mile/hr}{1m/s}\times 407.0m/s=895.4mile/hr](https://tex.z-dn.net/?f=407.0m%2Fs%3D%5Cfrac%7B2.2mile%2Fhr%7D%7B1m%2Fs%7D%5Ctimes%20407.0m%2Fs%3D895.4mile%2Fhr)
Therefore, the speed in miles per hour is 22 mile/hr.
The conversion used for meter to yard
1m = 1.09 yard
The conversion used for second to hour is:
![1s=\frac{1}{60}min](https://tex.z-dn.net/?f=1s%3D%5Cfrac%7B1%7D%7B60%7Dmin)
The conversion used for meter per second to mile per hour is:
![1m/s=\frac{1.09yard}{frac{1}{60min}}](https://tex.z-dn.net/?f=1m%2Fs%3D%5Cfrac%7B1.09yard%7D%7Bfrac%7B1%7D%7B60min%7D%7D)
![1m/s=65.4yard/min](https://tex.z-dn.net/?f=1m%2Fs%3D65.4yard%2Fmin)
As we are given the speed of 407.0 meter per second. Now we have to determine the speed in yards per min
![1m/s=65.4yard/min](https://tex.z-dn.net/?f=1m%2Fs%3D65.4yard%2Fmin)
So, ![407.0m/s=\frac{65.4yard/min}{1m/s}\times 407.0m/s=26617.8yard/min](https://tex.z-dn.net/?f=407.0m%2Fs%3D%5Cfrac%7B65.4yard%2Fmin%7D%7B1m%2Fs%7D%5Ctimes%20407.0m%2Fs%3D26617.8yard%2Fmin)
Therefore, the speed in yard per min is 26617.8 yard/min
Answer:
the final temperature is T=305.63 K
Explanation:
using the Stephan-Boltzmann equation for black bodies
q = σ*(T⁴-T₀⁴)
where
q= heat flux = 155 W/m²+150 W/m² = 255 W/m²
σ= Stephan-Boltzmann constant = 5.67*10⁻⁸ W/m²K⁴
T= absolute temperature
T₀= absolute initial temperature = 255 K
solving for T
q = σ*(T⁴-T₀⁴)
T = (q/σ + T₀⁴)^(1/4)
replacing values
T = (q/σ + T₀⁴)^(1/4) = (255 W/m²/(5.67*10⁻⁸ W/m²K⁴) + (255 K)⁴)^(1/4) = 305.63 K
T=305.63 K
thus the final temperature is T=305.63 K
Answer:
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Explanation:
for me, but the best. . the first one. . the first one