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grin007 [14]
3 years ago
8

What is the % yield when 12g of Mg react with HCl to produce 0.2g of H2?

Chemistry
1 answer:
goblinko [34]3 years ago
5 0

Answer:

The yield is 20 %.

Explanation:

Mg + 2 HCl → MgCl2 + H2

(12 g Mg) / (24.30506 g Mg/mol) x (1 mol H2 / 1 mol Mg) x (2.015894 g H2/mol) = 0.9953 g H2.

(0.2 g) / (0.9953 g) = 0.20 = 20% yield

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If we take 2.2 grams of CO2, 6.02 X 1021 atoms of nitrogen and 0.03 gram atoms of sulphur , then the molar ratio of C, N, and O
Zanzabum

Answer: -

5 : 1 : 3

Explanation: -

Mass of CO₂ = 2.2 g

Molar mass of CO₂ = 44 g / mol

Number of moles of CO₂ = \frac{Mass}{Molar mass}

                                          = \frac{2.2}{44}

                                         = 0.05 mol

Number of atoms of nitrogen = 6.02 x 10²¹

Number of moles of nitrogen = \frac{Number of atoms of nitrogen}{Avogadro's number}

                                                 = \frac{6.02x1021}{6.02x1023}

                                                = 0.01 mol

0.03 gram atom of sulphur means 0.03 moles of sulphur.

Thus the mole ratio of CO₂ : N : S = 0.05 : 0.01 : 0.03

                                                         = 5 : 1 : 3

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4 years ago
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Conservation of Energy is the principle stating…
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Answer:

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A solution is composed of 1.15 mL of diethyl ether (C4H10O, density=0.7134 g/mL) dissolved in 78.85 mL of dichloromethane (CH2Cl
jeka94

Answer:

Molarityof the solution is 0.1375 M.

Explanation:

We will first find the number of moles of diethyl ether (C4H10O)  by finding its molar mass and measured mass.

Molar mass of diethyl ether (C4H10O) = 74.12 g.

Now, volume of diethyl ether (C4H10O) = 1.15 mL and its density = 0.7134 g/mL.

Therefore,  measured mass of diethyl ether (C4H10O) = volume x  density = 1.15 mL x 0.7134 g/mL = 0.82 g.

Now, number of moles of diethyl ether (C4H10O) = \dfrac{Measured \ mass}{ Molar\ mass}= \frac{0.82\ g}{74.12\ g}

= 0.011 Moles.

Volume of the solution = volume of diethyl ether + volume of dichloromethane = 1.15 mL + 78.85 mL = 80 mL.

Now, molarity of the solution = Number of moles of diethyl ether / Volume of the solution( in  mL) x 1000 =  \dfrac {0.011}{80}\times 1000 = 0.1375\ M

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What was Antoine Henri Becquerel studying when he discovered radioactivity?
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Becquerel was studying the properties of X-Rays when he discovered radioactivity. His original theory was that X- Rays arose from uranium absorbing...

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