A small region of a cancer patient’s brain is exposed for 24.0 min to 475 Bq of radioactivity from⁶⁰Co for treatment of a tumor.
<h3>What is
tumor?</h3>
The Latin word for swelling is tumor. The term "tumor" is frequently used by laypeople to refer to cancerous growths, while the medical term "neoplasme" (sometimes known as "new-formation") is more appropriate in this context. A tumor can be benign or malignant; the last case is when it is the result of a cancerous growth.
The development of swelling on or within the body may also result from a variety of causes, including the toename of vocht (oedeem), an uncontrolled (lichaamsvijandige) toename of the number of cells, or a combination of the two.
A building on the hillside next to a valley is primarily made of oedeem, possibly combined with red blood cells by a blood vessel severing. There is oedeem, ontsteking cells, and pus splatter on an ontsteking, such as a steenpuist. There is a holte that is filled with a talc-like substance next to an atheroomcyst. A hutchrat is also a (goedaardige)
To learn more about tumor from the given link:
brainly.com/question/21003009
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Mole - one of the most important concepts in chemistry - is a kind of link to go from the microworld of atoms and molecules in a normal macrocosm grams and kilograms.
In chemistry often have to consider large numbers of atoms and molecules. For fast and efficient calculation made using the weighing method. But it is necessary to know the weight of individual atoms and molecules. In order to identify the molecular weight must be added the weight of all atoms in the compound.
Reaction 1 : yes
Reaction 2 : no
<h3>Further explanation</h3>
The metal activity series is expressed in voltaic series
Li-K-Ba-Ca-Na-Mg-Al-Mn- (H2O) -Zn-Cr-Fe-Cd-Co-Ni-Sn-Pb- (H) -Cu-Hg-Ag-Pt-Au
The more to the left, the metal is more reactive (easily release electrons) and the stronger reducing agent
The more to the right, the metal is less reactive (harder to release electrons) and the stronger oxidizing agent
So that the metal located on the left can push the metal on the right in the redox reaction
From activity series of Halogen :
F₂>Cl₂>Br₂>I₂
F₂ is the strongest oxidizing agent
1. Reaction
Cl₂ + 2Rbl - 2RbCI+ I₂
Cl₂>I₂⇒reaction can occur⇒yes, reactions will take place.
2. Reaction
I₂ + NiBr₂ - NI₂ + Br₂
Br₂>I₂⇒Reaction can't occur⇒no, reaction will not take place
Answer : 58.44 g
<h3>Further explanation</h3>
The reaction
mole ratio :
Na : Cl : NaCl = 1 : 1 : 1
Molar mass of Na : 22,989769 g/mol = 22.99 g/mol
Molar mass of Cl : 35,453 g/mol= 35.45 g/mol
Molar mass of NaCl : 58,44 g/mol
Let's check the mol for reactant (Na and Cl) and product(NaCl)
Then the reactants are completed reacting because it matches the mole ratio, which is 1: 1
so that the mole of the product can be determined from the mol Na or Cl, which is 1
The data set is missing in the question. The data set is given in the attachment.
Solution :
a). In the table, there are four positive examples and give number of negative examples.
Therefore,
and
The entropy of the training examples is given by :
= 0.9911
b). For the attribute all the associating increments and the probability are :
+ -
T 3 1
F 1 4
Th entropy for is given by :
![$\frac{4}{9}[ -\frac{3}{4}\log\left(\frac{3}{4}\right)-\frac{1}{4}\log\left(\frac{1}{4}\right)]+\frac{5}{9}[ -\frac{1}{5}\log\left(\frac{1}{5}\right)-\frac{4}{5}\log\left(\frac{4}{5}\right)]$](https://tex.z-dn.net/?f=%24%5Cfrac%7B4%7D%7B9%7D%5B%20-%5Cfrac%7B3%7D%7B4%7D%5Clog%5Cleft%28%5Cfrac%7B3%7D%7B4%7D%5Cright%29-%5Cfrac%7B1%7D%7B4%7D%5Clog%5Cleft%28%5Cfrac%7B1%7D%7B4%7D%5Cright%29%5D%2B%5Cfrac%7B5%7D%7B9%7D%5B%20-%5Cfrac%7B1%7D%7B5%7D%5Clog%5Cleft%28%5Cfrac%7B1%7D%7B5%7D%5Cright%29-%5Cfrac%7B4%7D%7B5%7D%5Clog%5Cleft%28%5Cfrac%7B4%7D%7B5%7D%5Cright%29%5D%24)
= 0.7616
Therefore, the information gain for is
0.9911 - 0.7616 = 0.2294
Similarly for the attribute 
the associating counts and the probabilities are :
+ -
T 2 3
F 2 2
Th entropy for is given by :
![$\frac{5}{9}[ -\frac{2}{5}\log\left(\frac{2}{5}\right)-\frac{3}{5}\log\left(\frac{3}{5}\right)]+\frac{4}{9}[ -\frac{2}{4}\log\left(\frac{2}{4}\right)-\frac{2}{4}\log\left(\frac{2}{4}\right)]$](https://tex.z-dn.net/?f=%24%5Cfrac%7B5%7D%7B9%7D%5B%20-%5Cfrac%7B2%7D%7B5%7D%5Clog%5Cleft%28%5Cfrac%7B2%7D%7B5%7D%5Cright%29-%5Cfrac%7B3%7D%7B5%7D%5Clog%5Cleft%28%5Cfrac%7B3%7D%7B5%7D%5Cright%29%5D%2B%5Cfrac%7B4%7D%7B9%7D%5B%20-%5Cfrac%7B2%7D%7B4%7D%5Clog%5Cleft%28%5Cfrac%7B2%7D%7B4%7D%5Cright%29-%5Cfrac%7B2%7D%7B4%7D%5Clog%5Cleft%28%5Cfrac%7B2%7D%7B4%7D%5Cright%29%5D%24)
= 0.9839
Therefore, the information gain for is
0.9911 - 0.9839 = 0.0072
Class label split point entropy Info gain
1.0 + 2.0 0.8484 0.1427
3.0 - 3.5 0.9885 0.0026
4.0 + 4.5 0.9183 0.0728
5.0 -
5.0 - 5.5 0.9839 0.0072
6.0 + 6.5 0.9728 0.0183
7.0 +
7.0 - 7.5 0.8889 0.1022
The best split for observed at split point which is equal to 2.
c). From the table mention in part (b) of the information gain, we can say that produces the best split.
