Answer:
<em> 8 large frames and 13 small frames</em>
Step-by-step explanation:
<u><em>Given:</em></u><em>
$18 each = large frames</em>
<em>$8 each = small frames</em>
<u><em>To Find:</em></u>
<em>⇒ Bought 21 frames for $248, find how many of each type she bought</em>
<u><em>Solve:</em></u>
<em>1 Large frame costs = 18 $</em>
<em>Therefore, x large frames costs = 18x $</em>
<em>{where x is the number of large frames she bought}</em>
<em>1 Small frame costs = 8 $</em>
<em>Therefore, x Small frames costs = 8y $</em>
<em>{where y is the number of small frames she bought}</em>
<em>By the given condition :</em>
<em>18x + 8y = 248 {equation 1}</em>
<em>x + y = 21 {equation 2}</em>
<em>Solve these equations simultaneously, from second equation we get :</em>
<em>x = 21- y</em>
<em>18⋅(21−y)+8y= 248</em>
<em>378 - 18y+8y = 248</em>
<em>-10y = -130</em>
<em>y = 13</em>
<em>Put y = 13 in eq x = 21- y</em>
<em>x = 21 - y</em>
<em>x = 21 - 13</em>
<em>x = 8</em>
<em>So the woman bought 8 large frames and 13 small frames.</em>
<em />
<u><em>~lenvy~</em></u>
