Answer:
Step-by-step explanation:
Hello!
To test if boys are better in math classes than girls two random samples were taken:
Sample 1
X₁: score of a boy in calculus
n₁= 15
X[bar]₁= 82.3%
S₁= 5.6%
Sample 2
X₂: Score in the calculus of a girl
n₂= 12
X[bar]₂= 81.2%
S₂= 6.7%
To estimate per CI the difference between the mean percentage that boys obtained in calculus and the mean percentage that girls obtained in calculus, you need that both variables of interest come from normal populations.
To be able to use a pooled variance t-test you have to also assume that the population variances, although unknown, are equal.
Then you can calculate the interval as:
[(X[bar]_1-X[bar_2) ± 
* 
]
[(82.3-81.2) ± 1.708* (6.11*
]
[-2.94; 5.14]
Using a 90% confidence level you'd expect the interval [-2.94; 5.14] to contain the true value of the difference between the average percentage obtained in calculus by boys and the average percentage obtained in calculus by girls.
I hope this helps!
This problem is quite simple, but it may seem tricky at first.
y is a function of x, so replace y with f(x)
You get f(x) = 2x - 4
D is your answer.
Have an awesome day! :)
Answer:
y=-9
Step-by-step explanation:
slope intercept form: y=mx+b, m being the slope
y=6 times -3
since there isn't a y intercept, you can't really put it in standard form unless I missed a step.
y= -9
Note the slope intercept form: y = mx + b, in which m = slope
Isolate the y. Note the equal sign, what you do to one side, you do to the other. First, add 3x to both sides
-3x (+3x) + 6y = (+3x) + 12
6y = 3x + 12
Fully isolate the y. Divide 6 from both sides (and to all terms)
(6y)/6 = (3x + 12)/6
y = (3x)/6 + (12)/6
Simplify
y = (1/2)x + 2
y = 0.5x + 2 is your equation.
The slope is direclty left of the x (or the m variable). In this case, it is 0.5
0.5 is your answer (or 1/2 if wanted in fraction form)
~
Answer:
c.) aₙ = 5 × 4ⁿ⁻¹
Explanation:
Geometric sequence: aₙ = a(r)ⁿ⁻¹
where 'a' resembles first term of a sequence, 'r' is the common difference.
Here sequence: 5, 20, 80, 320,...
First term (a) = 5
Common difference (d) = second term ÷ first term = 20 ÷ 5 = 4
Hence putting into equation: aₙ = 5(4)ⁿ⁻¹
