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ryzh [129]
3 years ago
14

Help!!!!! stuck on this

Mathematics
1 answer:
8090 [49]3 years ago
7 0
I hope this helps you




Pythagorean



hypothenus ^2=base^2+height ^2



hypothenus ^2=15^2+20^2



hypothenus ^2=225+400



hypothenus ^2=625



hypothenus ^2=25
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Consider the equation x+4=−2x+19. Let f(x)=x+4and g(x)=−2x+19. The graph of each function is shown. Coordinate plane with the gr
Svetach [21]

The point of intersection of both graphs will have the coordinate (5, 9).

<h3>What is the Point of Intersection of the Graph?</h3>

We are given the functions;

f(x) = x + 4

g(x) = -2x + 19

Now, the point of intersection of both graphs is when both functions are equal which is at f(x) = g(x). Thus;

x + 4 = -2x + 19

x + 2x = 19 - 4

3x = 15

x = 15/3

x = 5

Thus;

f(x) = 5 + 4 = 9

g(x) = -2(5) + 19 = 9

Thus, the point of intersection of both graphs will have the coordinate (5, 9)

Read more about Graph Intersection at; brainly.com/question/11337174

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4 0
1 year ago
A light bulb consumes 600 watt-hours per day. How long does it take to consume 2250 watt-hours?
Alexus [3.1K]
If a light bulb consumes 600 per day, then you need to divide 2250 by 600. So it would be around 3.75 days
3 0
3 years ago
The lengths of pregnancies are normally distributed with a mean of 268 days and a standard deviation of 15 days. a. Find the pro
Bogdan [553]

Answer:

Step-by-step explanation:

Let X be the length of pregnancy.

X is N(268, 15)

a) Prob of pregnancy lasting 307 days or longer

= P(X>307) = P(Z>\frac{307-268}{15} )\\=P(Z>2.6)\\

=0.5-0.4953

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b) Lowest 2% is 2nd percentile

Z=-2.55

X score = 268-2.55(15)

= 229.75 days

If length of days >230 days then it is not premature.

4 0
3 years ago
Solve the equation. 9 = – x + 8
lord [1]

Answer:

x = - 1

Step-by-step explanation:

Given

9 = - x + 8 ( subtract 8 from both sides )

1 = - x ( multiply both sides by - 1 )

- 1 = x ⇒ x = - 1

5 0
3 years ago
Q3. A student plans a method to prepare pure crystals of copper sulfate.
andreev551 [17]

Answer:

1) The student didn't add copper sulfate but instead he added calcium carbonate.

2) The heated solution should be left to get bigger crystals and should not be instantly allowed to evaporate.

3) He should use copper carbonate not calcium carbonate.

4) Sulfuric acid was added instead of hydrochloric acid.

5) Add solid excessively so that all of the acid is retained.

6) Filter the solution to remove unreacted solid.

7) Heat gently, so the crystals will start to appear.

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2 years ago
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