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klio [65]
3 years ago
14

100 points and brainliest

Mathematics
2 answers:
Otrada [13]3 years ago
7 0

Answer:

-40<T<140

the circle would be open since we are using only the normal greater than/ less than. It would also move to the right.

nordsb [41]3 years ago
6 0

Answer: Hello Luv......

Hope this helps. Mark me brianest please... Anna ♥

Step-by-step explanation:

Answer: -40 < T < 140

From the question, we are informed that the gas that the driver uses freezes at −40° F and evaporates at 140° F.

To get the inequality to represent the temperatures at which the gas in the truck will remain in liquid form, we should note that the temperature will be lower than 140°F but more than -40°F. This can be expressed as:

= -40 < T < 140

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Please help me guys with this. Thank you.
denis23 [38]

Answer:

You would mirror it along the X axis

Step-by-step explanation:

The points that they are on now, reverse the positivity/negativity (in this case negativity)

Into positivity , because the f has been reversed in its positivity/negativity.

5 0
3 years ago
What integer represents a 5-point loss added to a 2–point gain?
Hoochie [10]

Answer:

-3

Step-by-step explanation:

5 point loss is -5,

2 point gain is (+)2.

If it's added, the expression will be -5 + 2.

-5 + 2 is -3.

-3 is an integer, because integers are whole numbers and their opposites.

If this helped, please mark it brainliest.. unless there is a better answer. Thanks.

7 0
3 years ago
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nalin [4]

Answer:

900

Step-by-step explanation:

8 0
3 years ago
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Are the expressions equivalent? Select all that apply.
Natalija [7]
A, B, and C are the correct answers
8 0
3 years ago
PLEASE HELP WITH QUESTION, MARKING BRAINLIEST + POINTS!!!
JulijaS [17]
1. This is a very easy question as you can just plug in 2 x-values and get the y-value, run a line through it, and you are done. 

For example,
x = 2t
x = 2(2) = 4
x = 2(3) = 6

Now, you know there are points at (2, 4) and (3, 6).

2. This one is a little tricky, but all it's saying is that it has a specified domain. The parametric equation only works for values -2 ≤ t ≤ 3. So, you can do the exact same thing, except your line will only exist for points through the x-values -2 and 3. Let's plug in numbers:

y = t + 5
y = -2 + 5 = 3
y = 1 + 5 = 6

Now you know that this line runs through (-2, 3) and (1, 6). Remember, your line starts at -2 and ends at 3. It can't go any further than that.
8 0
3 years ago
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