Answer:
1. B - Aa x Aa = 25% chance AA, which is the only genotype that results in sickle-cell. Aa is called "sickle-cell trait'; it isn't the full disease.
2. A - Aa x aa = we know will produce no homozygous dominant
3. B - RR x Rr = 1/2 chance of Rr (same problem as #5)
4. A - Bb x Bb = 1:2:1 ratio
5. B - WW x Ww = 1/2 chance of Ww
6. D - AABbCC has 5 dominant alleles, which is the most out of the four options
7. C - the one with the fewest dominant alleles will be the most green and the most successful in the environment
When a haemophilic carrier female marries a haemiphilic man then due to ther genotypes
Xc=carrier of haemophilia
Xn=normal
Y=dont carry haemophilic genes
so here we go!
XcY cross with XcXn
genotypes of ther offsprings
1=XcXc
2=XcXn
3=XcY
4=XnY
so from whole 4 there is 50% parobability
I believe that would be natural selection
the strands make up a mollecular compound consisting of the parts of the remaining dna that came from the parents which originated from jesus
It is unethical because it is using an unconscious host/body as testing device, which could potentially be inefficient.
