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taurus [48]
11 months ago
7

If the equation x^2 + 16x + c = 0 has only one real solution, the value of c must equal

Mathematics
1 answer:
kumpel [21]11 months ago
3 0

If the equation x² + 16x + c = 0 has only one real solution, the value of c is equal to 64.

<h3>Discriminant: </h3>

The quadratic formula includes the discriminant, which comes after the square root. The discriminant of a quadratic equation is important because it indicates the quantity and kind of solutions.  

The formula for the Discriminant of a Quadratic Equation ax²+bx +c = 0 is given by

<h3>               Discriminant Δ = b² - 4ac </h3>

Here we have

x² + 16x + c = 0 equation has only one real solution

Compare given equation with ax²+ bx + c = 0

=> a = 1, and b = 16  

As we know when an equation has only one real solution

then its Discriminant will be equal to zero

=> b² - 4ac = 0

By the above values,

=> 16² - 4(1)c = 0  

=> 256 - 4c = 0

=> 4c = 256

=> c = 256/4

=> c = 64

Therefore,

If the equation x² + 16x + c = 0 has only one real solution, the value of c is equal to 64.

 

Learn more about Discriminant at

brainly.com/question/15884086

#SPJ1

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