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taurus [48]
1 year ago
7

If the equation x^2 + 16x + c = 0 has only one real solution, the value of c must equal

Mathematics
1 answer:
kumpel [21]1 year ago
3 0

If the equation x² + 16x + c = 0 has only one real solution, the value of c is equal to 64.

<h3>Discriminant: </h3>

The quadratic formula includes the discriminant, which comes after the square root. The discriminant of a quadratic equation is important because it indicates the quantity and kind of solutions.  

The formula for the Discriminant of a Quadratic Equation ax²+bx +c = 0 is given by

<h3>               Discriminant Δ = b² - 4ac </h3>

Here we have

x² + 16x + c = 0 equation has only one real solution

Compare given equation with ax²+ bx + c = 0

=> a = 1, and b = 16  

As we know when an equation has only one real solution

then its Discriminant will be equal to zero

=> b² - 4ac = 0

By the above values,

=> 16² - 4(1)c = 0  

=> 256 - 4c = 0

=> 4c = 256

=> c = 256/4

=> c = 64

Therefore,

If the equation x² + 16x + c = 0 has only one real solution, the value of c is equal to 64.

 

Learn more about Discriminant at

brainly.com/question/15884086

#SPJ1

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AURORKA [14]
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julsineya [31]

The equation of the newsletter function is C(x) = 75 + 0.25x and the function values are C(0) = 75, C(100) = 100, C(200) = 125 and  C(300) = 150

<h3 /><h3>How to determine the newsletter function?</h3>

From the question, the given parameters are

Initial charge = $75.00

Rate per copy = $0.25 per copy

The equation of the newsletter function is then calculated as

Total = Initial charge + Rate per copy x Number of copies

Let x represents the number of copies

So, we have

Total = Initial charge + Rate per copy x x

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When x = 0, we have

C(0) = 75 + 0.25 x 0 = 75

When x = 100, we have

C(100) = 75 + 0.25 x 100 = 100

When x = 200, we have

C(200) = 75 + 0.25 x 200 = 125

When x = 300, we have

C(300) = 75 + 0.25 x 300 = 150

Read more about linear equations at

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Kipish [7]

Answer:

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