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2 years ago

Decide whether the relation is a function

Mathematics

2 answers:

soldi70 [24.7K]2 years ago

6 0

Answer:

function is the correct answer in my opinion hope it's helps you

zmey [24]2 years ago

4 0

Step-by-step explanation:

im not sure but,

<h3>i think its a Function</h3>

<h2>hope it helps.</h2>

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Which sentence describes the end behavior of the function shown? pls help!!!!

grin007 [14]

Answer:

Step-by-step explanation:

because that is the correct answer believe me

5 0

2 years ago

Is 3/4 greater than 7/8?

yKpoI14uk [10]

3/4 = (2*3) / (2* 4) = 6/8

7/8.

Is 3/4 greater than 7/8?
Is like asking is 6/8 greater than 7/8? Because 3/4 is equivalent to 6/8.

The answer is No.

3 0

3 years ago

Read 2 more answers

Find the length of the curve. R(t) = 7t, 3 cos(t), 3 sin(t) , −2 ≤ t ≤ 2

Leviafan [203]

we are given

$r(t)=(7t,3cos(t),3sin(t))$

we can find x , y and z

$x=7t,y=3cos(t),z=3sin(t))$

now, we can use arc length formula

$L=\int\limits^a_b {\sqrt{(x')^2+(y')^2+(z')^2} } \, dt$

now, we can find derivative

$x'=7,y'=-3sin(t),z'=3cos(t))$

now, we can plug values

and we get

$L=\int _{-2}^2\sqrt{7^2+\left(-3\sin \left(t\right)\right)^2+\left(3\cos \left(t\right)\right)^2}dt$

$L=\int _{-2}^2\sqrt{7^2+9}dt$

$=\sqrt{58}\cdot \:2-\left(-2\sqrt{58}\right)$

$L=4\sqrt{58}$ ...........Answer

8 0

3 years ago

The sum of 5 consecutive odd integers is 2,555. What is the sum of the first, third, and last integer?

Lilit [14]

Answer:

The sum of the first, third, and last integer is 1533.

Step-by-step explanation:

<u><em>Step 1: You need to create a equation first:</em></u>

n + n + 2 + n + 4 + n + 6 + n + 8 = 2555

<u><em>How did I make the equation?</em></u>

If n is odd number, n + 2 must be the consecutive odd number

5 , 5 + 2 , 5 + 4 , 5 + 6 , 5 + 8

5, 7, 9, 11, 13 ALL CONSECUTIVE ODD NUMBERS

<u><em>Step 2: Simplifying the equation</em></u>

n + n + 2 + n + 4 + n + 6 + n + 8 = 2555

5n + 20 = 2555

<u><em>Step 3: Solving the equation, with explanation</em></u>

5n + 20 = 2555 Subtract 20 on both sides

5n = 2535 Isolate the variable by dividing 5 on both sides

n = 507

<u><em>Step 4: Plug in the value</em></u>

n + n + 2 + n + 4 + n + 6 + n + 8

507, 507 + 2 , 507 + 4 , 507 + 6 , 507 + 8

507, 509, 511, 513, 515

<u><em>Step 5: Solve the sum of the first, third, and last integer</em></u>

507 + 511 + 515 = 1533

<u><em>Step 6: THE ANSWER</em></u>

1533

<h3><u><em>Hope this helps!!! </em></u></h3><h3><u><em>Please mark this as brainliest!!! </em></u></h3><h3><u><em>Thank You!!! </em></u></h3><h3><u><em>:)</em></u></h3>

8 0

3 years ago

<img src="https://tex.z-dn.net/?f=24x%5E%7B2%7D%2Bbx%5E%7B2%7D%20%3D25x%5E%7B2%7D" id="TexFormula1" title="24x^{2}+bx^{2} =25x^{

Liula [17]

Answer:

x = 0

Step-by-step explanation:

Subtract 25x^2 from both sides

24x^2 + bx^2 - 25x^2 - 25x^2

Simplify

bx^2 - x^2 = 0

Factor bx^2 - x^2: x^2(b - 1)

bx^2 - x^2

Factor out common term x^2

= x^2 (b - 1)

x^2(b - 1) = 0

Using the Zero Factor Principle: If ab = 0 then a = 0 or b = 0

x^2 = 0

Apply rule x^n = 0 x = 0

x = 0

8 0

2 years ago