3 years ago

Quadrilateral ABCD is a rhombus with an area of 20 square inches.

Mathematics

1 answer:

Ugo [173]3 years ago

8 0

Answer:

area of rhombus =1/2 d1×d2

20=1/2 ×10×d2

d2=4

intersection of diagonal make right angle and cut in equal parts

d1/2=10/2=5

d2/2=4/2=2

use Pythagoras in right angle to bide side

side^2= 5^2 +2^2

side = √29

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Nesterboy [21]

Answer:

Option C

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Step-by-step explanation:

A quadratic equation will have equal roots if its Discriminant is equal to zero.

the discriminant in this case is $b^{2}- 4 ac$

considering the equation,

$9x^{2} + 8xk+8 = 0$

a = 9, b= 8k, c=8

Replacing the variables in the original equation with their respective values, we will have:

$8k^{2}- 4 \times 9 \times 8=0\\64k^{2}=288\\k=\sqrt{288/64} =\sqrt{9/2}$

Note: The values of k are meant to be + or -2.12 as seen from the workings

However, these are not in the options given. the closest choice to it

is + or - 3

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Answer:

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