<h2>Hello!</h2>
The answer is: A. 2π
<h2>Why?</h2>First, in order to make it easier, let's convert the numbers into entire or decimal numbers.
So, ordering it:
C, D, A, B
So, Y=A=6.28
Have a nice day!
Which function has only one x-intercept at (-6, 0)?
2 answers:
Answer:
<h2>The function f(x) = (x - 6)(x - 6) has only one x-intercept. But at (6, 0) not at (-6, 0).</h2>Step-by-step explanation:
The intercept form of a quadratic equation (parabola):
p, q - x-intercepts
Therefore
The function f(x) = x(x - 6) = (x - 0)(x - 6) has two x-intercepts at (0, 0) and (6, 0)
The function f(x) = (x - 6)(x - 6) has only one x-intercept at (6, 0)
The function f(x) = (x + 6)(x - 6) = (x - (-6))(x - 6)
has two x-intercept at (-6, 0) and (6, 0)
The function f(x) = (x + 1)(x + 6) = (x - (-1))(x - (-6))
has two x-intercepts at (-1, 0) and (-6, 0).
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Answer:
1, -6
Step-by-step explanation:
Since there are alike numbers, add them together.
4x+x= 5x
Now the function is: f(x)= +5x-6
The function is in +bx+c form.
So find the factors of a x c = b.
Factors of -6(a) that fits (b)5 is (-1,6).
Then you just factor it:
f(x)= +5x-6
(x-1)(x+6)
x-1= 0 x+6=0
+1 +1 -6 -6
x=1 x=-6
Those are the real zeroes: 1, -6