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3 years ago

Which function has only one x-intercept at (-6, 0)?

Mathematics

2 answers:

Lelu [443]3 years ago

6 0

Answer:

<h2>The function f(x) = (x - 6)(x - 6) has only one x-intercept. But at (6, 0) not at (-6, 0).</h2>

Step-by-step explanation:

The intercept form of a quadratic equation (parabola):

$y=a(x-p)(x-q)$

p, q - x-intercepts

Therefore

The function f(x) = x(x - 6) = (x - 0)(x - 6) has two x-intercepts at (0, 0) and (6, 0)

The function f(x) = (x - 6)(x - 6) has only one x-intercept at (6, 0)

The function f(x) = (x + 6)(x - 6) = (x - (-6))(x - 6)

has two x-intercept at (-6, 0) and (6, 0)

The function f(x) = (x + 1)(x + 6) = (x - (-1))(x - (-6))

has two x-intercepts at (-1, 0) and (-6, 0).

shusha [124]3 years ago

3 0

Answer:

the answer is d on edge

Step-by-step explanation:

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I’ve attached my work
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Have a nice rest of your day :)

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