Answer:
18 ft^2
Step-by-step explanation:
This quadrilateral is a parallelogram.
Area = base × height
= 6 × 3
= 18 ft^2
Answer:
(C.) d= sqrt (x2-x1)^2+(y2-y1)^2, where d is the distance between points (x1,y1) and (x2,y2).
Step-by-step explanation:
Answer:
V = 67.0206 m3
Step-by-step explanation:
Answer:
8.6 N
Step-by-step explanation:
Let T be the unknown force
Let θ be the slope of the inclined plane to horizontal
Let φ be the angle of the force to the plane
Let μ be the coefficient of static friction
Let m be the mass
Let N be the Normal force of plane on mass
Let Ff be the friction force which will have a maximum at μN
Let g be gravity
Forces acting <u>parallel to the plane</u>. Upslope is positive
For minimum force T, friction will be max and acting upslope.
F = ma
Tcosφ - mgsinθ + Ff = m(0)
Tcosφ - mgsinθ + μN = 0
Tcosφ - mgsinθ + μ(mgcosθ - Tsin(θ + φ)) = 0
T(cosφ - μsin(θ + φ)) + μmgcosθ - mgsinθ = 0
T = mg(sinθ - μcosθ) / (cosφ - μsin(θ + φ))
T = 2(9.8)(sin30 - 0.25cos30) / (cos30 - 0.25sin(30 + 30))
T = 8.5547537...
Given: <span>2x-y-3=0.
find </span>equation for the line perpendicular to the given line that goes through the given point:<span>
(2;-1)koord of direction vector (i`m not know how it is called at you, because i'm from russia)</span><span>
=> (x-0)/2=(y-4)/-1 (</span>canonical <span>equation)
=>x+2y-8=0(general </span><span>equation)
</span>
<span>further:
{x+2y-8=0
{2x-y-3 =0 => y=13/5 x=14/5
(14/5; 13/5) - koord point on line
</span>|dist|=sqrt( (14/5-0)^2 + (13/5-4)^2 ) = sqtr(7.72) = 2.78
Удачи!
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