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anastassius [24]
4 years ago
11

Which function has only one x-intercept at (-6, 0)?

Mathematics
2 answers:
Lelu [443]4 years ago
6 0

Answer:

<h2>The function f(x) = (x - 6)(x - 6) has only one x-intercept. But at (6, 0) not at (-6, 0).</h2>

Step-by-step explanation:

The intercept form of a quadratic equation (parabola):

y=a(x-p)(x-q)

p, q - x-intercepts

Therefore

The function f(x) = x(x - 6) = (x - 0)(x - 6) has two x-intercepts at (0, 0) and (6, 0)

The function f(x) = (x - 6)(x - 6) has only one x-intercept at (6, 0)

The function f(x) = (x + 6)(x - 6) = (x - (-6))(x - 6)

has two x-intercept at (-6, 0) and (6, 0)

The function f(x) = (x + 1)(x + 6) = (x - (-1))(x - (-6))

has two x-intercepts at (-1, 0) and (-6, 0).

shusha [124]4 years ago
3 0

Answer:

the answer is d on edge

Step-by-step explanation:

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Answer:

b = -152

Step-by-step explanation:

  1. 7 + 12 = 19
  2. Plug 19 in: \frac{b}{19} = -8  
  3. Multiply each side by 19 to cancel out the 19 under b. It should now look like this: b = -152

I hope this helps!

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Answer:

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Step-by-step explanation:

I hope this helps! Have a nice day!

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