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Sergeu [11.5K]
3 years ago
10

A 45.0L gas cylinder contains 988 He at 23 degrees C what is the pressure inside the cylinder​

Chemistry
1 answer:
gregori [183]3 years ago
8 0

Answer:

P = 133.4 atm

Explanation:

Given data:

Mass of helium = 988 g

Volume = 45.0 L

Temperature = 23°C (23+273= 296 K)

Pressure of cylinder = ?

Solution:

Number of moles of helium:

Number of moles = mass/ molar mass

Number of moles = 988 g/ 4 g/mol

Number of moles = 247 mol

Pressure:

PV = nRT

P = nRT/V

P = 247 mol × 0.0821. atm. L/mol. K × 296 K / 45 L

P = 6002.5 / 45 L

P = 133.4 atm

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A galvanic cell at a temperature of 42°C is powered by the following redox reaction:
WARRIOR [948]

Answer:

1.99V

Explanation:

Balanced redox reaction equation:

3CU2+(aq) + 2Al(s) ------> 3Cu(s) + 2Al3+(aq)

E°cell= E°cathode- E°anode

E°cell= 0.34-(-1.66)

E°cell= 2.0V

From Nernst equation:

E= E°cell - 0.0592/n logQ

E= 2.0 - 0.0592/6 log [3.43]/[1.63]

E= 2.0- 0.0032

E= 1.99V

4 0
3 years ago
Read 2 more answers
To investigate the reactivity of metals a student uses four metals. Each time they added 1 g of the metal to 25 cm³ of sulfuric
Mazyrski [523]

Answer:

Volume of the sulfuric acid (25cm³), same mass of each metal (1g)

Explanation:

In an experiment, the CONTROL VARIABLE also known as constant is the variable that is kept unchanged for all groups in an experiment. This is done in order not to influence the outcome of the experiment.

In this case, students are trying to investigate the reactivity of four different metals. They added 1 g of each metal to 25cm³ of sulfuric acid and recorded the temperature change. Based on the explanation of control variable above, the VOLUME OF SULFURIC ACID (25cm³) and the MASS OF EACH METAL (1g) are the CONTROL VARIABLES because they are the same or unchanged in this experiment.

5 0
3 years ago
1. What is the potential energy of a 8 kg ball that is at a height of 20 m?
weqwewe [10]

Answer:

1. 1568 J

2. 0 J

3. 1176 J

Explanation:

PE = mgh

(PE = Potential Energy) = (m = mass)(g = gravitational force which is 9.8)(h = height)

1. (3)(9.8)(20) = 1568 J

2. PE = (3)(9.8)(0) = 0 J

3. (5)(9.8)(24) =  1176 J

4 0
3 years ago
(3×10^6)^2<br>write in scientific notation
umka2103 [35]
The answer to the question

6 0
3 years ago
In standardizing the solution of aqueous sodium hydroxide, a chemist overshoots the end point and adds too much naoh(aq). would
irinina [24]

Answer: Concentration of NaOH calculated will be underestimated.

Explanation:

End point is an observational point , which tells us about the completion of reaction between the titrant (solution in burette) and titre(solution in conical flask) in titration experiment.

In this case , NaOH is titrant whose concentration is unknown.

M_1=\text{molarity of titre} , M_2=\text{molarity of NaOH}

V_1=\text{volume of titre} , V_2=\text{volume of NaOH}

M_1V_1=M_2V_2

M_2=\frac{M_1V_1}{V_2}....(1)

According to question a chemist overshoots the end point and adds to much of NaOH solution, which means increase in the value of V_2.

Then the value of M_2 in equation (1), will get lowered , which means that the concentration of NaOH was lower than that of the actual value. Hence underestimated concentration of NaOH.




8 0
3 years ago
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