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2 years ago

I need help with these two questions, i been stuck for 2 hours

Chemistry

1 answer:

PilotLPTM [1.2K]2 years ago

3 0

1. The mass of Fe2O3 required will be 51.29 grams

2. The mass of Cu that will be formed is 36 kg

<h3>Stoichiometric problems</h3>

1) The equation of the reaction goes thus: $2Fe_2O_3 + 3Pt --- > 3PtO_2 + 4Fe$

Mole ratio of Fe to Fe2O3 = 2:1

Mole of 35.9 g Fe = 35.9/56 = 0.6411 mol

Equivalent mole of Fe2O3 = 0.6411/2 = 0.3205 mol

Mass of 0.3205 mol Fe2O3 = 0.3205 x 160 = 51.29 grams

2) $2CuO --- > 2Cu + O_2$

Mole ratio of CuO to Cu = 1:1

Mole of 45 kg CuO = 45000/80 = 562.5 mol

Equivalent mole of Cy = 562.5 mol

Mass of 562.5 mol of Cu = 562.5 x 64 = 36,000 grams or 36 kg

More on stoichiometric problems can be found here: brainly.com/question/15047541

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