Question

I need help with these two questions, i been stuck for 2 hours

Answer 1

1.  The mass of Fe2O3 required will be 51.29 grams

2. The mass of Cu that will be formed is 36 kg

Stoichiometric problems

1) The equation of the reaction goes thus: $2Fe_2O_3 + 3Pt --- > 3PtO_2 + 4Fe$

Mole ratio of Fe to Fe2O3 = 2:1

Mole of 35.9 g Fe = 35.9/56 = 0.6411 mol

Equivalent mole of Fe2O3 = 0.6411/2 = 0.3205 mol

Mass of 0.3205 mol Fe2O3 = 0.3205 x 160 = 51.29 grams

2) $2CuO --- > 2Cu + O_2$

Mole ratio of CuO to Cu = 1:1

Mole of 45 kg CuO = 45000/80 = 562.5 mol

Equivalent mole of Cy = 562.5 mol

Mass of 562.5 mol of Cu = 562.5 x 64 = 36,000 grams or 36 kg

More on stoichiometric problems can be found here: brainly.com/question/15047541

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