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LenKa [72]
2 years ago
15

A galvanic cell at a temperature of 42°C is powered by the following redox reaction:

Chemistry
2 answers:
Assoli18 [71]2 years ago
5 0

Answer:

The cell voltage of the given cell is 2.01 V

Explanation:

3Cu^{2+}(aq.)+2Al(s)\rightarrow 3Cu(s)+2Al^{3+}(aq.)

Oxidation half reaction:

2Al(s)\rightarrow 2Al^{3+}(aq,1.63M)+3e^-;E^o_{Al^{3+}/Al}=-1.66V

Reduction half reaction:

3Cu^{2+}(aq,3.43M)+2e^-\rightarrow 3Cu(s);E^o_{Cu^{2+}/Cu}=0.34V

Oxidation reaction occurs at anode and reduction reaction occurs at cathode.

To calculate the E^o_{cell} of the reaction, we use the equation:

E^o_{cell}=0.34-(-1.66)=2.00V

To calculate the EMF of the cell, we use the Nernst equation, which is:

E_{cell}=E^o_{cell}-\frac{2.303RT}{nF}\log \frac{[Al^{3+}]^2}{[Cu^{2+}]^3}

where,

E_{cell} = electrode potential of the cell = ? V

E^o_{cell} = standard electrode potential of the cell = +2.00 V

R = Gas constant = 8.314 J/mol.K

T = temperature = 42^oC=[42+273]K=315K

F = Faraday's constant = 96500

n = number of electrons exchanged = 6

[Cu^{2+}]=3.43M[Al^{3+}]=1.63M

E_{cell}=2.00-\frac{2.303\times 8.314\times 315}{6\times 96500}\times \log(\frac{(1.63)^2}{(3.43)^3})

E_{cell}=2.01

Thus, the cell voltage of the given cell is 2.01

WARRIOR [948]2 years ago
4 0

Answer:

1.99V

Explanation:

Balanced redox reaction equation:

3CU2+(aq) + 2Al(s) ------> 3Cu(s) + 2Al3+(aq)

E°cell= E°cathode- E°anode

E°cell= 0.34-(-1.66)

E°cell= 2.0V

From Nernst equation:

E= E°cell - 0.0592/n logQ

E= 2.0 - 0.0592/6 log [3.43]/[1.63]

E= 2.0- 0.0032

E= 1.99V

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Agata [3.3K]

Answer : The moles of NH_3 formed are, 22.3 moles.

Explanation : Given,

Moles of N_2H_4 = 16.72 mol

The given chemical reaction is:

3N_2H_4(l)\rightarrow 4NH_3(g)+2N_2(g)

From the balanced chemical reaction, we conclude that:

As, 3 moles of N_2H_4 react to give 4 moles of NH_3

So, 16.72 moles of N_2H_4 react to give \frac{4}{3}\times 16.72=22.3 moles of NH_3

Therefore, the moles of NH_3 formed are, 22.3 moles.

8 0
3 years ago
Wind power is:
12345 [234]
Answer) All of the above
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The central core of an atom is called the __?
PilotLPTM [1.2K]

Answer: Atomic Nucleus!

Explanation: All atoms have a dense central core called the atomic nucleus. Forming the nucleus are two kinds of particles: protons, which have a positive electrical charge, and neutrons, which have no charge.

(Yes, it was from google.)

6 0
3 years ago
15.3 g of nano3 were dissolved in 100g of water in a calorimeter. The temperature of the water drops from 25.00°c to 21.56°c. Ca
Arturiano [62]

Answer:

0.259 kJ/mol ≅ 0.26 kJ/mol.

Explanation:

  • To solve this problem, we can use the relation:

<em>Q = m.c.ΔT,</em>

where, Q is the amount of heat absorbed by ice (Q = ??? J).

m is the mass of the ice (m = 100.0 g).

c is the specific heat of water (c of ice = 4.186 J/g.°C).

ΔT is the difference between the initial and final temperature (ΔT = final T - initial T = 21.56°C - 25.0°C = -3.44°C).

<em>∵ Q = m.c.ΔT</em>

∴ Q = (100.0 g)(4.186 J/g.°C)(-3.44°C) = -1440 J = -1.44 kJ.

<em>∵ ΔH = Q/n</em>

n = mass/molar mass = (100.0 g)/(18.0 g/mol) = 5.556 mol.

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3 0
3 years ago
Find the volume in milliliters of 2.00 mol of an ideal gas at 36°C and a pressure of 1120 torr.
hram777 [196]

Answer:

V = 34430 mL

Explanation:

Given data:

Volume in mL = ?

Number of moles of gas = 2.00 mol

Temperature = 36°C (36+273= 309K)

Pressure of gas = 1120 torr

Solution:

Formula:

PV = nRT

V = nRT/P

V = 2.00 mol ×62.4 torr • L/mol · K × 309K / 1120 torr

V = 38563.2 torr • L / 1120 torr

V = 34.43 L

L to mL

34.43 L ×1000 mL / 1 L

34430 mL

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2 years ago
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