Find the area of the circle with the given radius or diameter. Use = 3.14. d=13

Eliminate the parameter. x = t2 + 1, y = t2 - 1

Alexus [3.1K]

$\bf \begin{cases}
x=t^2+1\implies x-1=\boxed{t^2}\\
y=t^2-1\\
----------\\
y=\boxed{x-1}-1\\
y=x-2
\end{cases}$

4 0

3 years ago

Read 2 more answers

Please help asap will give brainlist

vagabundo [1.1K]

Answer:

Both are equations, one is linear, one is not linear boom

Step-by-step explanation:

4 0

3 years ago

The formula for the volume of a rectangular prism is lwh What would be a interpretation of that in words. I put the products of

borishaifa [10]

Answer:

the formula for a rectangular prism is length* Height* Width

Step-by-step explanation:

8 0

3 years ago

PLS HELP ILL GIVE BRAINLIEST!

lesantik [10]

Answer:

B

Step-by-step explanation:

-the base angles are 34, so the total value of both base angles is 68

-an isosceles triangle is equal to 180

-subtract 68 from 180 for the answer, so the equation is 68+x=180

hope this helps, comment in you have a question :)

8 0

2 years ago

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Based on an indication that mean daily car rental rates may be higher for Boston than for Dallas, a survey of eight car rental c

Elina [12.6K]

Answer:

$t=\frac{(47 -44)-(0)}{3\sqrt{\frac{1}{8}+\frac{1}{9}}}=2.058$

The degrees of freedom are:

$df=8+9-2=15$

And the p value would be:

$p_v =P(t_{15}>2.058) =0.0287$

Since we have a p value lower than the significance level given of 0.05 we can reject the null hypothesis and we can conclude that the true mean for car rental rates in Boston are signiﬁcantly higher than those in Dallas

Step-by-step explanation:

Data given

$n_1 =8$ represent the sample size for group Boston

$n_2 =9$ represent the sample size for group Dallas

$\bar X_1 =47$ represent the sample mean for the group Boston

$\bar X_2 =44$ represent the sample mean for the group Dallas

$s_1=3$ represent the sample standard deviation for group Boston

$s_2=3$ represent the sample standard deviation for group Dallas

We can assume that we have independent samples from two normal distributions with equal variances and that is:

$\sigma^2_1 =\sigma^2_2 =\sigma^2$

Let the subindex 1 for Boston and 2 for Dallas we want to check the following hypothesis:

Null hypothesis: $\mu_1 \leq \mu_2$

Alternative hypothesis: $\mu_1 > \mu_2$

The statistic is given by this formula:

$t=\frac{(\bar X_1 -\bar X_2)-(\mu_{1}-\mu_2)}{S_p\sqrt{\frac{1}{n_1}+\frac{1}{n_2}}}$

Where t follows a t student distribution with $n_1+n_2 -2$ degrees of freedom and the pooled variance $S^2_p$ is given by this formula:

$\S^2_p =\frac{(n_1-1)S^2_1 +(n_2 -1)S^2_2}{n_1 +n_2 -2}$

Replacing we got:

$\S^2_p =\frac{(8-1)(3)^2 +(9 -1)(3)^2}{8 +9 -2}=9$

And the deviation would be just the square root of the variance:

$S_p=3$

The statitsic would be:

$t=\frac{(47 -44)-(0)}{3\sqrt{\frac{1}{8}+\frac{1}{9}}}=2.058$

The degrees of freedom are:

$df=8+9-2=15$

And the p value would be:

$p_v =P(t_{15}>2.058) =0.0287$

Since we have a p value lower than the significance level given of 0.05 we can reject the null hypothesis and we can conclude that the true mean for car rental rates in Boston are signiﬁcantly higher than those in Dallas

5 0

3 years ago