Do the opposite of the problem
A.) To find the maximum height, we can take the derivative of h(t). This will give us the rate at which the horse jumps (velocity) at time t.
h'(t) = -32t + 16
When the horse reaches its maximum height, its position on h(t) will be at the top of the parabola. The slope at this point will be zero because the line tangent to the peak of a parabola is a horizontal line. By setting h'(t) equal to 0, we can find the critical numbers which will be the maximum and minimum t values.
-32t + 16 = 0
-32t = -16
t = 0.5 seconds
b.) To find out if the horse can clear a fence that is 3.5 feet tall, we can plug 0.5 in for t in h(t) and solve for the maximum height.
h(0.5) = -16(0.5)^2 + 16(-0.5) = 4 feet
If 4 is the maximum height the horse can jump, then yes, it can clear a 3.5 foot tall fence.
c.) We know that the horse is in the air whenever h(t) is greater than 0.
-16t^2 + 16t = 0
-16t(t-1)=0
t = 0 and 1
So if the horse is on the ground at t = 0 and t = 1, then we know it was in the air for 1 second.
Answer:
Step-by-step explanation:
<u><em>The picture of the question in the attached figure</em></u>
The point P is the center of the circle (the drawing is not a scale )
step 1
Find the measure of angle ∠CPD
we know that
---> by supplementary angles (form a linear pair)
step 2
Find the measure of arc DC
we know that
<u><em>Central angle</em></u> is the angle that has its vertex in the center of the circumference and the sides are radii of it
so
----> by central angle
therefore
Answer:
HL
Step-by-step explanation:
Use the HL Congruence Theorem to prove that the triangles are congruent.
<span>To determine the value of the unknown number in this item, we have to let x be that number such that 0.75x is equal to 27. To calculate for the value of x, we divide 27 by 3/4. This operation gives us the value of 36. Hence, the answer to this item is 36.</span>
