By looking at the graph, we can visually determine that the value of y when point x = -2 is <u>-4.</u>
Answer: I think that the answer is either 11 avocados or 9
Step-by-step explanation:
21-2.50 is 18.50
with this he can buy 9 with 15 dollars but he still has 3.50 left over
if he uses this left over change he can buy two more which would make 11.
If this is wrong I am sorry!
Answer:
Right Triangle, Acute Triangle, and Obtuse Triangle
Step-by-step explanation:
I can't draw it here but the right triangle has a side of 90°.
An acute triangle has a side smaller than 90°.
An obtuse triangle has a side bigger than 90°.
Answer:
(a) MAE = 5.20
(b) MSE = 10
(c) MAPE = 38.60%
(d) Forecast for week 7 = 14
Step-by-step explanation:
Note: See the attached excel for the calculations of the Error, Error^2, and Error %.
(a) mean absolute error
MAE = Total of absolute value of error / Number of observations considered = |Error| / 5 = 26 / 5 = 5.20
(b) mean squared error
MSE = Total of Error^2 / Number of observations considered = Error^2 / 5 = 150 / 5 = 10
(c) mean absolute percentage error (Round your answer to two decimal places.)
MAPE = Total of Error % / Number of observations considered = Error % / 5 = 193.02 / 5 = 38.60%
(d) What is the forecast for week 7?
Since the forecast is based on the naive method (most recent value), the forecast for week 7 is value for week 6. Therefore, we have:
Forecast for week 7 = 14
Answer:
Step-by-step explanation:
Given that:
Population Mean = 7.1
sample size = 24
Sample mean = 7.3
Standard deviation = 1.0
Level of significance = 0.025
The null hypothesis:

The alternative hypothesis:

This test is right-tailed.

Rejection region: at ∝ = 0.025 and df of 23, the critical value of the right-tailed test 
The test statistics can be computed as:



t = 0.980
Decision rule:
Since the calculated value of t is lesser than, i.e t = 0.980 <
, then we do not reject the null hypothesis.
Conclusion:
We conclude that there is insufficient evidence to claim that the population mean is greater than 7.1 at 0.025 level of significance.