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3 years ago

Bette had 280 kilograms of bolts and put the same amount into each of 8 boxes. How

Mathematics

1 answer:

Elenna [48]3 years ago

4 0

Answer:

Step-by-step explanation:

You have to divide 280 by 8 and that's how you get it.

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How does tan 135 degrees compare to tan -135 degrees

Anna007 [38]

Evaluating the tangent function for the two values we obtain the following:
tan 135=tan(135+180)=tan 315=-1

next:
tan -135=tan(180-135)=tan 45=1
thus comparing the two we see that tan 135 is negative while tan -135 is positive

3 0

3 years ago

Which classification correctly describes the polygon?

sergiy2304 [10]

Answer is (A) because it is concave and it has 8 sides

5 0

3 years ago

Which of the following numbers is 90 divisible by? 2,3,4,5,6,9,10

Mrac [35]

Answer:

2,3,5,6,9,10

Step-by-step explanation:

To do this, we can look at how each value divides into 90. If it produces a whole number, they will be consider to be divisible

$90/2=45\\\\90/3=30\\\\90/4=22.5\\\\90/5=18\\\\90/6=15\\\\90/9=10\\\\90/10=9$

This means 4 is the only value that is not divisible into 90

8 0

3 years ago

Read 2 more answers

A cube has a surface area of 486 cm2. What is the side length ?

astraxan [27]

A Cube, has all equal sides, namely, the length, width and height
are all equal to each other

so.. notice the picture added here
you have really, 6 squares, stacked up to each other at the edges

so...what is the Area of one of those squares?
well, if the sides are equal, let's say the side is "x" long, then
the Area is $x\cdot x \implies x^2$

well, you have 6 of those squares, thus $\bf \textit{surface area of a cube}=
\begin{cases}
(x\cdot x)+\\
(x\cdot x)+\\
(x\cdot x)+\\
(x\cdot x)+\\
(x\cdot x)+\\
(x\cdot x)\\
 --------------\\
 x^2+x^2+x^2+x^2+x^2\\
6x^2
\end{cases}
\\\\
\textit{we know the Area is }486\ cm^2\qquad thus
\\\\
\textit{surface area}=6x^2\implies 486=6x^2$

solve for "x", to get one side's length

3 0

3 years ago

Plz write this on paper help me and send it❤️

vovangra [49]

Answer:

1. $27^{\frac{2}{3} } =9$

2. $\sqrt{36^{3} } =216$

3. $(-243)^{\frac{3}{5} } =-27$

4. $40^{\frac{2}{3}}=4\sqrt[3]{25} =4325$

5. Step 4: $(\frac{343}{27}) ^{-1} =\frac{27}{343}$

6. $D. -72cd^{7}$

Step-by-step explanation:

Use the following properties:

$a^{\frac{x}{y} } =\sqrt[x]{a^{y} }$

$\sqrt[n]{ab} =\sqrt[n]{a} \sqrt[n]{b}$

$a^{-n} =\frac{1}{a^{n} }$

$(xy)^{z} =x^{z} y^{z} \\\\$

$(x^{y}) ^{z} =x^{yz}$

$x^{y} x^{z} =x^{y+z}$

So:

1. $27^{\frac{2}{3} } =\sqrt[3]{27^{2}} =\sqrt[3]{729} }=9$

2. $\sqrt{36^{3} } =\sqrt{36*36*36} =\sqrt{36} \sqrt{36} \sqrt{36} =6*6*6=216$

3. $(-243)^{\frac{3}{5} } =\sqrt[5]{-243^{3} } =\sqrt[5]{-14348907} =-27$

4. $40^{\frac{2}{3}}=\sqrt[3]{40^{2} } =\sqrt[3]{2^{6} 5^{2} } =\sqrt[3]{2^{6} } \sqrt[3]{5^{2} } =2^{\frac{6}{3} } 5^{\frac{2}{3} } =4 *5^{\frac{2}{3} } =4\sqrt[3]{5^{2} } =4\sqrt[3]{25}=4325$

5. $(\frac{343}{27}) ^{-1} =\frac{1}{\frac{343}{27} } =\frac{27}{343}$

$(-8c^{9} d^{-3} )^{\frac{1}{3} } *(6c^{-1}d^{4})^{2} =\sqrt[3]{-8} c^{3} d^{-1} 36c^{-2} d^{8} \\\\-2c^{3} d^{-1} 36c^{-2} d^{8}=-72cd^{7}$

7 0

3 years ago