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ki77a [65]
3 years ago
13

156 rounded to the nearest hundred is?

Mathematics
1 answer:
aliina [53]3 years ago
6 0
200 because 156 is closer to 200 than 100
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2 less than 7 times a number c is written as
sammy [17]

Answer:

7c-2

Step-by-step explanation:

7 times a number c tells us that we want to multiply c by seven. 2 less than tells us that we want to subtract 2 from 7c.

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2 years ago
Henry runs each lap in 4 minutes. He will run at most 11 laps today. What are the possible numbers of minutes he will run today?
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Answer:

Step-by-step explanation:

Time taken in each lap = 4 min

Total laps = 11

Total time = 11 x 4 = 44min

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Determine the slope of the line. Please explain the answer . If you hurry I’ll mark brainliest
Daniel [21]

Answer:

2/4

Step-by-step explanation:

Rise over run. you go up 2 and right 4

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3 years ago
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Michaela works in a bank she is paid £19200 per annum how much does she get per month
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in a year she earns=19200

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4 0
3 years ago
The coordinates of rhombus ABCD are A(–4, –2), B(–2, 6), C(6, 8), and D(4, 0). What is the area of the rhombus? Round to the nea
a_sh-v [17]
Check the picture below.

so the rhombus has the diagonals of AC and BD, now keeping in mind that the diagonals bisect each, namely they cut each other in two equal halves, let's find the length of each.

\bf ~~~~~~~~~~~~\textit{distance between 2 points}
\\\\
A(\stackrel{x_1}{-4}~,~\stackrel{y_1}{-2})\qquad 
C(\stackrel{x_2}{6}~,~\stackrel{y_2}{8})\qquad \qquad 
%  distance value
d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2}
\\\\\\
AC=\sqrt{[6-(-4)]^2+[8-(-2)]^2}\implies AC=\sqrt{(6+4)^2+(8+2)^2}
\\\\\\
AC=\sqrt{10^2+10^2}\implies AC=\sqrt{10^2(2)}\implies \boxed{AC=10\sqrt{2}}\\\\
-------------------------------

\bf ~~~~~~~~~~~~\textit{distance between 2 points}
\\\\
B(\stackrel{x_1}{-2}~,~\stackrel{y_1}{6})\qquad 
D(\stackrel{x_2}{4}~,~\stackrel{y_2}{0})\qquad \qquad BD=\sqrt{[4-(-2)]^2+[0-6]^2}
\\\\\\
BD=\sqrt{(4+2)^2+(-6)^2}\implies BD=\sqrt{6^2+6^2}
\\\\\\
BD=\sqrt{6^2(2)}\implies \boxed{BD=6\sqrt{2}}

that simply means that each triangle has a side that is half of 10√2 and another side that's half of 6√2.

namely, each triangle has a "base" of 3√2, and a "height" of 5√2, keeping in mind that all triangles are congruent, then their area is,

\bf \stackrel{\textit{area of the four congruent triangles}}{4\left[ \cfrac{1}{2}(3\sqrt{2})(5\sqrt{2}) \right]\implies 4\left[ \cfrac{1}{2}(15\cdot (\sqrt{2})^2) \right]}\implies 4\left[ \cfrac{1}{2}(15\cdot 2) \right]
\\\\\\
4[15]\implies 60

7 0
2 years ago
Read 2 more answers
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